Answer:
The power produced by the turbine is 23309.1856 kW
Explanation:
h₁ = 3755.39
s₁ = 7.0955
s₂ = sf + x₂sfg =
Interpolating fot the pressure at 3.25 bar gives;
570.935 +(3.25 - 3.2)/(3.3 - 3.2)*(575.500 - 570.935) = 573.2175
2156.92 +(3.25 - 3.2)/(3.3 - 3.2)*(2153.77- 2156.92) = 2155.345
h₂ = 573.2175 + 0.94*2155.345 = 2599.2418 kJ/kg
Power output of the turbine formula =
![Q - \dot{W } = \dot{m}\left [ \left (h_{2}-h_{1} \right )+\dfrac{v_{2}^{2}- v_{1}^{2}}{2} + g(z_{2}-z_{1})\right ]](https://tex.z-dn.net/?f=Q%20-%20%5Cdot%7BW%20%7D%20%3D%20%5Cdot%7Bm%7D%5Cleft%20%5B%20%5Cleft%20%28h_%7B2%7D-h_%7B1%7D%20%20%5Cright%20%29%2B%5Cdfrac%7Bv_%7B2%7D%5E%7B2%7D-%20v_%7B1%7D%5E%7B2%7D%7D%7B2%7D%20%2B%20g%28z_%7B2%7D-z_%7B1%7D%29%5Cright%20%5D)
Which gives;
![560 - \dot{W } = 8\left [ \left (2599.2418-3755.39 \right )+\dfrac{15^{2}- 60^{2}}{2} \right ]](https://tex.z-dn.net/?f=560%20-%20%5Cdot%7BW%20%7D%20%3D%208%5Cleft%20%5B%20%5Cleft%20%282599.2418-3755.39%20%20%5Cright%20%29%2B%5Cdfrac%7B15%5E%7B2%7D-%2060%5E%7B2%7D%7D%7B2%7D%20%5Cright%20%5D)
= -8*((2599.2418 - 3755.39)+(15^2 - 60^2)/2 ) = -22749.1856
= -22749.1856 - 560 = -23309.1856 kJ
= 23309.1856 kJ
Power produced by the turbine = Work done per second = 23309.1856 kW.
The correct answer is A; True.
Further Explanation:
This is a correct phrase that is important to learn when owning any type of vehicle. When a car battery is dead, it can usually be jump started by using another cars battery or a portable battery charger. It is extremely important to put the positive battery cable on the positive battery post. Then the negative cable will be placed on the negative car battery post and the negative ground wire can be anywhere on the car except on the battery.
The car needs to be connected properly for a few minutes before trying to start the car. This helps the car battery to get enough "juice" to start. If the battery cables are placed wrong this can cause sparks to come out of the cables/battery and cause bodily harm.
Learn more about car batteries at brainly.com/question/7734062
#LearnwithBrainly
Answer:
a) 0.684
b) 0.90
Explanation:
Catalyst
EO + W → EG
<u>a) calculate the conversion exiting the first reactor </u>
CAo = 16.1 / 2 mol/dm^3
Given that there are two stream one contains 16.1 mol/dm^3 while the other contains 0.9 wt% catalyst
Vo = 7.24 dm^3/s
Vm = 800 gal = 3028 dm^3
hence Im = Vin/ Vo = (3028 dm^3) / (7.24dm^3/s) = 418.232 secs = 6.97 mins
next determine the value of conversion exiting the reactor ( Xai ) using the relation below
KIm =
------ ( 1 )
make Xai subject of the relation
Xai = KIm / 1 + KIm --- ( 2 )
<em>where : K = 0.311 , Im = 6.97 ( input values into equation 2 )</em>
Xai = 0.684
<u>B) calculate the conversion exiting the second reactor</u>
CA1 = CA0 ( 1 - Xai )
therefore CA1 = 2.5438 mol/dm^3
Vo = 7.24 dm^3/s
To determine the value of the conversion exiting the second reactor ( Xa2 ) we will use the relation below
XA2 = ( Xai + Im K ) / ( Im K + 1 ) ----- ( 3 )
<em> where : Xai = 0.684 , Im = 6.97, and K = 0.311 ( input values into equation 3 )</em>
XA2 = 0.90
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Answer:
C. Have your hazard lights on
Explanation:
Speeding up will cause an accident
Counter steering is not easy to do
Slowing down my result in you being rear ended