Standard entropy of the compounds of interest are as follows,
= 212.1 J/K.mol
= 205.0 J/K.mol
= 213.6 J/K.mol
= 69.9 J/K.mol
Now for the reaction:
<span>C6H12O6(s) + 6O2(g) —->6CO2(g) + 6H2O(l)
</span>
ΔS°reaction = ∑
- ∑
∴ ΔS°reaction =( 6
+ 6
) - (
+ 6
= 205.0 J/K.mol)
∴ ΔS°reaction = [6 (213.6) + 6 (69.9 )] - [(212.1) + 6(205.0)]
∴ ΔS°reaction = 258.9 ≈ 262 J/ K mol.
Thus, correct answer is option C
Answer:
n8ce question and answer is time taken
Atom B(+6), Atom X(+2), Atom Q(+1), Atom P (-17)