A passenger elevator travels from the first floor to the 60th floor, a distance of 210 m, in 35s. What is the elevator’s speed?

To form a stable ion will magnesium gain or lose electrons how many electrons

pashok25 [27]

The electronic structure of Magnesium is 2,8,2
so in order to form a stable ions, it will lose 2 electrons.
Now, the proton number of Mg is 12, electron number is 10.
It will show positive charge.
Conclusion: Mg will lose 2 electrons to form Mg2+.

4 0

3 years ago

CuCl2 Determine the name of this compound according to IUPAC nomenclauture. A) copper chloride B) copper (I) chloride C) copper

faltersainse [42]

The answer is <span>copper (II) chloride</span>

5 0

4 years ago

Read 2 more answers

X-rays have a wavelength small enough to image individual atoms, but are challenging to detect because of their typical frequenc

Cerrena [4.2K]

Explanation:

Given: $\lambda = 8.38\:\text{nm} = 8.38×10^{-9}\:\text{m}$

Its frequency $\nu$ is defined as

$\nu = \dfrac{c}{\lambda} = \dfrac{3×10^8\:\text{m/s}}{8.38×10^{-9}\:\text{m}}$

$\:\:\:\:= 3.58×10^{16}\:\text{Hz}$

7 0

3 years ago

Write the balanced standard combustion reaction for the c5h7on3s2

AlexFokin [52]

Answer:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Explanation:

When C5H7ON3S2 under go Combustion, the following are obtained as illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

Now, let us balance the equation. This is illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

There are 3 atoms of N on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of C5H7ON3S2 and 6 in front of N2 as shown below:

4C5H7ON3S2 + O2 —> CO2 + H2O + 6N2 + S2

There are 20 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 20 in front of CO2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + H2O + 6N2 + S2

There are 28 atoms on H on the left side and 2 atoms on the right side. It can be balance by putting 14 in front of H2O as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + S2

There are 8 atoms of S on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of S2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, there are a total of 54 atoms of O on the right side and 6 atoms on the left side

It can be balance by putting 25 in front of O2 as shown below:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, we can see that the equation is balanced.

4 0

3 years ago

A sample of aluminium has a mass of 54 gram. What is the mass of the same number of magnesium atom.

Arada [10]

Answer:

48g of Magnesium.

Explanation:

We know that:

Mole=given mass/molar mass

Then, moles of aluminum = 54/27 = 2.

A/c to question ,

For 2 moles of magnesium it's mass is 2×24=48g.

Hence, the required mass for same number of magnesium atoms is 48g.

(Hope this helps can I pls have brainlist (crown)☺️)

5 0

3 years ago