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lutik1710 [3]
3 years ago
13

Sand at a beach becomes very warm after being exposed to sunlight for many hours due to what type of heat transfer?

Chemistry
2 answers:
erastova [34]3 years ago
7 0

Answer:

C

Explanation:

When lie down on hot sand, the energy flows from the sand to your body by conduction. Conduction is the transfer of heat between two things that touch each other.

andreev551 [17]3 years ago
3 0

Answer:

B

Explanation:

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Trehalose, sophorose and turanose are disaccharides. Trehalose is found in the cocoons of some insects, sophorose turns up in a
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First structure is sophorose, second structure is turanose, third structure is trehalose, fourth structure is none of the above.

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Argon, which comprises almost 1 percent of the atmosphere, is approximately 27 times more abundant than CO2 but does not contrib
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B. Argon's vibrational energy is not excited by infrared radiation.

Explanation:

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Answer: Christine Herman & L.G Wade Jr., "2010". Organic Chemistry: Reaction of Alkane, 7e, Pearson Education, Radford University, Radford, VA.

Explanation:

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7 0
3 years ago
How many electrons does titanium have in the D orbital in its ground state electron configuration
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Titanium atoms have 22 electrons and the shell structure is 2.8. 10.2. The ground state electron configuration of ground state gaseous neutral titanium is [Ar].

6 0
3 years ago
in order to find the molar mass of an unknown compound, a research scientist prepared a solution of 0.930 g of an unknown in 125
PtichkaEL [24]

Answer:

Molar mass→ 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol

Explanation:

Let's apply the formula for freezing point depression:

ΔT = Kf . m

ΔT = 74.2°C - 73.4°C → 0.8°C

Difference between the freezing T° of pure solvent and freezing T° of solution

Kf = Cryoscopic constant → 5.5°C/m

So, if we replace in the formula

ΔT = Kf . m → ΔT / Kf = m

0.8°C / 5.5 m/°C = m → 0.0516 mol/kg

These are the moles in 1 kg of solvent so let's find out the moles in our mass of solvent which is 0.125 kg

0.0516 mol/kg . 0.125 kg = 6.45×10⁻³ moles. Now we can determine the molar mass:

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