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3 years ago

Les étapes nous permettant de sentir une tarte aux pommes

Chemistry

1 answer:

Dmitry [639]3 years ago

3 0

Answer:

L'ordre correct est le suivant;

1. Les cils olfactifs capturent les molécules chimiques odorantes

2. Le signal des molécules chimiques est transformé en impulsions nerveuses

3. L'influx nerveux est transféré au cerveau par le nerf olfactif au bulbe olfactif du cerveau antérieur

4. Les odeurs sont perçues

Explanation:

Pour sentir la pomme, l'air autour de la pomme est inhalé rapidement pour aider les produits chimiques odorants à entrer dans la cavité nasale.

La cavité nasale a des cellules spéciales qui sont réceptives aux produits chimiques odorants, qui envoient un message au cerveau lors de la liaison au produit chimique par le nerf olfactif. Lorsque le message arrive au bulbe olfactif du cerveau antérieur, il est analysé et l'odeur est identifiée et / ou reconnue.

Par conséquent, l'ordre correct est le suivant;

1. 1. Les cils olfactifs captent les molécules chimiques odorantes

2. 2. Le signal des molécules chimiques est transformé en impulsions nerveuses

3. 4. L'influx nerveux est transféré au cerveau par le nerf olfactif au bulbe olfactif du cerveau antérieur

4. 3. Les odeurs sont perçues.

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2 years ago

A toxicologist studying mustard gas, S(CH2CH2Cl)2, a blistering agent, prepares a mixture of 0.675 M SCl2and 0.973 M C2H4 and al

Musya8 [376]

Answer:

The value of $K_p$ is 0.02495.

Explanation:

Initial concentration of $SCL_2$ gas = 0.675 M

Initial concentration of $C_2H_4$ gas = 0.973 M

Equilibrium concentration of mustard gas = 0.35 M

$SCl_2 (g) + 2 C_2H_4 (g)\rightleftharpoons S(CH_2CH_2Cl)_2(g)$

initially

0.675 M 0.973 M 0

At equilibrium ;

(0.675-0.35) M (0.973-2 × 0.35) M 0.35 M

The equilibrium constant is given as :

$K_c=\frac{[S(CH_2CH_2Cl)_2]}{[SCl_2][C_2H_4]^2}$

$=\frac{0.35 M}{(0.675-0.35) M\times ((0.973-2 × 0.35) M)^2}$

$K_c=14.45$

The relation between $K_p$ and $K_c$ are :

$K_p=K_c\times (RT)^{\Delta n}$

where,

$K_p$ = equilibrium constant at constant pressure = ?

$K_c$ = equilibrium concentration constant =14.45

R = gas constant = 0.0821 L⋅atm/(K⋅mol)

T = temperature = 20.0°C =20.0 +273.15 K=293.15 K

$\Delta n$ = change in the number of moles of gas = [(1) - (1 + 2)]=-2

Now put all the given values in the above relation, we get:

$K_p=14.45\times (0.0821L.atm/K.mol\times 293.15 K)^{-2}$

$K_p=6.2\times 10^{4}$

$K_p=0.02495$

The value of $K_p$ is 0.02495.

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2 years ago

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Answer:

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Explanation:

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2 years ago

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ziro4ka [17]

Answer:

Molecule

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Here's an example:

-- Sodium is a soft, slippery metal, that explodes when water touches it.

-- Chlorine is a poisonous green gas.

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3 years ago

How many moles of iron are there in 55.85g of Fe3O4

soldier1979 [14.2K]

Answer:

• Molecular mass of Iron (III) tetraoxide

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[ molar masses: Fe → 56, O → 16 ]

$\dashrightarrow \:{ \rm{232 \: g \: = 1 \: mole}} \\ \\ \dashrightarrow \: { \rm{55.85 \: g = ( \frac{55.85}{232}) \: moles }} \\ \\ \dashrightarrow \: { \boxed{ \tt{ = 0.24 \: moles}}}$

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