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Sliva [168]
3 years ago
6

The density of Diamond is 3.51 g/cm3, and the density of platinum is 21.43 g/cm3. If equal masses of diamond and platinum are tr

ansferred to equal volumes of water in separated graduated cylinders, which graduated cylinder would have the greatest volume change
Chemistry
1 answer:
Reptile [31]3 years ago
4 0

Answer:

Explanation:

Diamond has lesser density than platinum . So , if we take equal mass of both , the volume of mass of platinum will be far less .

The density of both diamond and platinum are  more than water so both of them will be drowned in water completely . They will not float . On being drowned , platinum will displace lesser volume of water because of its less volume . So volume change in case of platinum mass will be far less . The volume change for diamond will be more because of its bigger size.

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What causes convection currents in a gas or liquid?​
Genrish500 [490]

Answer:

Convection currents are caused by a temperature difference in gases and liquids. As one area becomes warmer than another the molecules have more energy and start vibrating more vigorously thus spreading out and becoming less dense. This means that the less dense parts will become more buoyant causing them to rise.

Explanation:

5 0
3 years ago
Read 2 more answers
3) A child has a toy balloon with a volume of 1.8 liters. The temperature of the balloon when it was filled was 22° C and the pr
mestny [16]

This is a combined gas law problem, according to which

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

where P is the pressure of the gas, V is the volume of the gas, and T is the temperature of the gas, and the subscripts 1 and 2 correspond to the initial and final conditions of the gas. In this problem, we are given the initial pressure, volume, and temperature of the gas in the balloon:

P₁ = 1.0 atm

V₁ = 1.8 L

T₁ = 295.15 K (K = °C + 273.15).

Moreover, we are given the final pressure and temperature of the gas in the balloon.

P₂ = 0.86 atm

T₂ = 281.15 K.

What we want to find is the final volume, V₂, which we can obtain by rearranging the combined gas equation to solve for V₂:

V_2=\frac{P_1V_1T_2}{T_1P_2} = \frac{(1.0 \text{ atm})(1.8 \text{ L})(281.15 \text{ K})}{(295.15 \text{ K})(0.86 \text{ atm})} \\ V_2 = 1.99 \text{ L}

This answer has three significant figures. However, the question as written would warrant an answer that comprises one significant figure (as 8 °C has only one sig fig). In that case, the answer would be 2 L. If the answer is to be given to two significant figures, the volume would then be 2.0 L.

8 0
3 years ago
Though hydrochloric acid is formed inside our body, it is not called organic acid. Why?​
Sphinxa [80]

Explanation:

Hydrochloric acid does not consider as organic acid because of the absence of carbon in it.

hope it helps

6 0
3 years ago
An unknown compound melting at 131 - 133 C. It is thought to be one of the following compounds: trans-cinnamic acid (133-134); b
Vesnalui [34]

Answer:

benzamide

Explanation:

Compound            melting Point ,ºC          Melting Pont Mixture, ºC

       X                          131 - 133

trans-cinnamic            133 - 134                      110 - 120

acid

benzamide                 128 - 130                       130-132

malic acid                   131   -133                        114 -124

Benzoin                      135 - 137                        108 - 116

The compound X is benzamide since the melting point range is the one closest to this compound (  130-132 ºC)

The reason there is not an exact match is not due due to the presence of impurities. The presence of impurities always lower the melting point ( it is a coligative property such as the melting point depresion of salt and water )

The reason for the deviation must be  be some other factors such as preparation of the sample in the capillary, errors in reading the thermometer, rate of heating, etc.

5 0
3 years ago
Hydrogen sulfide decomposes according to the following reaction, for which Kc=9.30E-8 at 700 degrees Celsius. 2 H2S(g) --> 2
Svetlanka [38]

Answer: The equilibrium concentration of H_2(g) at 700 degrees Celsius is 0.0012 M

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_c


Moles of  H_2S = 0.29 mole

Volume of solution = 3.0 L

Initial concentration of H_2S = \frac{0.29mol}{3.0L}=0.097M

The given balanced equilibrium reaction is,

                    2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

         Initial conc.         0.097 M           0M          0M

At eqm. conc.    (0.097-2x) M            (2x) M   (x) M

The expression for K_c is written as:

K_c=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}

K_c=\frac{(2x)^2\times x}{(0.097-2x)^2}

9.30\times 10^{-8}=\frac{(2x)^2\times x}{(0.097-2x)^2}

x=0.00060

Equilibrium concentration of [H_2]= 2x= 2\times 0.00060=0.0012M

6 0
3 years ago
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