Answer:
1. Hydrogen ions; acidic
2. Alkali; hydroxide ions; alkaline
3a. Sulfuric acid --> 2 Hydrogen ions + sulfate ion
H₂SO₄ --> 2H+ + SO₄²-
3b. Sodium hydroxide --> Sodium ion + Hydroxide ion
NaOH --> Na+ + OH-
Explanation:
1. Sulfuric acid releases hydrogen ions in solution. This makes the solution acidic.
Acids produce hydrogen ions when dissolved in aqueous solutions.
2. Sodium hydroxide is an alkali. It releases hydroxide ions in solution. This makes the solution alkaline.
Alkalis are soluble bases that produce hydroxide ions in solution.
3a. Sulfuric acid --> 2 Hydrogen ions + sulfate ions
H₂SO₄ --> 2H+ + SO₄²-
The equation above is for the ionization of sulfuric acid
b. Sodium hydroxide --> Sodium ion + Hydroxide ion
NaOH --> Na+ + OH-
The equation above is for the ionization of sodium hydroxide
A). 4
.........................
Answer: 0.30 M
Explanation:
According to the neutralization law,
where,
= molarity of 
solution = ?
= volume of solution = 24.6 ml
= molarity of 
solution = 0.222 M
= volume of solution = 33.0 ml
= valency of = 21
= valency of = 1
Therefore, the molarity of the HCI solution is 0.30 M
It is used as a before and after or step by step proces
