To solve this problem we will apply the concepts related to the conservation of momentum. Momentum can be defined as the product between mass and velocity. We will depart to facilitate the understanding of the demonstration, considering the initial and final momentum separately, but for conservation, they will be later matched. Thus we will obtain the value of the mass. Our values will be defined as
Initial momentum will be
After collision
Final momentum
From conservation of momentum
Replacing,
Answer:
0.5 m/s
Explanation:
From Newton's Third law of motion,
Momentum of the cannon = momentum of the flatcar.
mv = MV........................ Equation 1
Where m = mass of the cannon, v = velocity of the cannon, M = mass of the flatcar, V = Velocity of the flat car.
make V the subject of the equation
V = mv/M................... Equation 2
Given: m = 10 kg, v = 50 m/s, M = 1000 kg
Substitute into equation 2
V = 10×50/1000
V = 500/1000
V = 0.5 m/s
Hence the speed of the flatcar = 0.5 m/s
More work was done in the skateboard that came to a stop because the one that rolled across the room moved on a surface with less friction while the second board used more work to move on a surface with much friction.
(Missing figure with the % increase in mass due to the water uptake:
http://d2vlcm61l7u1fs.cloudfront.net/media%2Fac9%2Fac92f7ce-4a21-4ac5-af4b-6fea198a229b%2FphpUohikw.... )
The temperature coefficient
is given by
where K are the reaction rates, and T the temperatures.
From the table, the increases in temperature are always of 10C, so T2-T1=10, and the formula becomes
The reaction rates are simply the increase in mass due to water uptake. Therefore we have:
- from 5C to 15C:
- from 15C to 25C:
- from 25C to 35C:
b) The average Q10 is: