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mamaluj [8]
3 years ago
14

Which property describes a mixture? Select three options.

Chemistry
2 answers:
ss7ja [257]3 years ago
4 0

Answer:

1) It can be separated by physical methods.

2) It can appear different from different sources.

3) It cannot be described by a chemical symbol or formula.

Mixture is composed of at least two substances.

kakasveta [241]3 years ago
3 0

Answer:

It can be separated by physical methods.

2) It can appear different from different sources.

3) It cannot be described by a chemical symbol or formula.

Explanation:

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CH4(g) gas reacts with F2(g) to produce CH3F(g) and HF(g) .
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Answer:

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What is a common event due to transform plate movement at the San Andreas Fault Zone?
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Answer:

Earthquakes

Explanation:

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A sample of hydraulic acid has a volume of 2.3L. What is the volume of acid in gallons?
Assoli18 [71]

0.60759572 gal  is the volume of acid in gallons  in a sample of hydraulic acid .

<h3>What do mean by the term "gallons" ?</h3>

The gallon is a unit of measurement for volume and fluid capacity in both the US  units and the British imperial systems of measurement.

In SI base units, 1 Gal is equal to 0.01 m/s²

Since ,

1 L, l = 0.2641720524 gal

now, volume of acid in gallons is given by -

2.3 L, l = 2.3 × 0.2641720524 gal

=0.60759572 gal

Hence , 0.60759572 gal is the volume of acid in gallons  in a sample of hydraulic acid .

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Caffeine, a stimulant found in coffee, tea, and certain soft drinks, contains C, H, O, and N. Combustion of 1.000 mg of caffeine
Yuliya22 [10]

Answer:

  • <u>194 g/mol</u>

Explanation:

<u>1) Content of C:</u>

All the C atoms in the 1.000 mg of caffeine will be found in the 1.813 mg of CO₂.

  • Mass of C in 1.813 mg of CO₂

       Since the atomic mass of C is 12.01 g/mol and the molar of of CO₂ is 44.01, there are 12 mg of C in 44 mg of CO₂ and you can set the proporton:

       12.01 mg C / 44.01 mg CO₂ = x / 1.813 g CO₂

        ⇒ x = 1.813 × 12.01 / 44.01 g of C = 0.49475 mg of C

  • Number of moles of C

      number of moles = mass in g / atomic mass = 0.49475×10⁻³ g / 12.01 g/mol = 4.1195×10⁻⁵ moles = 0.041195 milimol

<u>2) Content of H</u>

All the H atoms in the 1.000 mg of caffeine will be found in the 0.4639 mg of H₂O

  • Mass of H in 0.4639 mg of H₂O

       Since the atomic mass of H is 1.008 g/mol and the molar of of H₂O is 18.015 g/mol, there are 2×1.008 mg of H in 18.015 mg of H₂O and you can set the proporton:

       2×1.008 mg H / 18.015 mg H₂O = x / 0.4639 mg H₂O

        ⇒ x = 0.4639 mg H₂O × 2 × 1.008 mg H / 18.015 mg H₂O = 0.051913 mg H

  • Number of moles of H

      number of moles = mass in g / atomic mass = 0.051913 ×10⁻³ g / 1.008 g/mol = 5.1501× 10⁻⁵ moles = 0.051501 milimol

<u>3) Content of N</u>

All the N atoms in the 1.000 mg of caffeine will be found in the 0.2885 mg of N₂

  • Mass of N in 0.2885 mg of N₂ is 0.2885 mg

  • Number of moles of N

      number of moles = mass in g / atomic mass = 0.2885 ×10⁻³ g / 14.007 g/mol = 2.0597× 10⁻⁵ moles = 0.020597 milimol

<u>4) Content of O</u>

The mass of O is calculated by difference:

  • Mass of O = mass of sample - mass of C - mass of H - mass of N

       Mass of O = 1.000 mg - 0.49475 mg C - 0.051913 mg H - 0.2885 mg N

     Mass of O = 0.1648 mg

  • Moles of O =  0.1648 × 10 ⁻³ g / 15.999 g/mol = 1.0303×10⁻⁵ mol = 0.01030 milimol

<u>5) Ratios</u>

Divide every number of mililmoles by the smallest number of milimoles:

  • C:  0.041195 / 0.01030 = 4
  • H: 0.051501 / 0.01030 = 5
  • N: 0.020597 / 0.01030 = 2
  • O: 0.01030 / 0.01030 = 1

  • C: 4
  • H: 5
  • N: 2
  • O: 1

<u>6) Empirical formula:</u>

  • C₄H₅N₂O₁

<u>7) Calculate the approximate mass of the empirical formula:</u>

  • 4 × 12 + 5 × 1 + 2 × 14 + 1 × 16 =  97 g/mol

So, since that number is not between 150 and 200 g/mol, multiply by 2: 97 × 2 = 194, which is between 150 and 200.

Thus, the estimate is 194 g/mol

7 0
3 years ago
A student titrated 20 ml of 0.410 m hcl with 0.320 m naoh. determine the volume of naoh needed at equivalence point
Aleksandr-060686 [28]

Answer:

25.6mL NaOH

Explanation:

We are given the Molarity of the solution (\frac{moles}{liters}) and the volume of the solution (.02L).

By multiplying the two together, we can find the moles of solution that are reacted with HCl.

moles = \frac{.410 moles}{L} *.02L

This gives us .0082 moles of HCl.

We then find the moles of NaOH that are needed to react with the HCl using the equation.

HCl + NaOH = NaCl + H_{2} O

As HCl and NaCl have a 1:1 ratio, we need .0082 mol of NaOH.

Dividing this value by the Molarity of the solution

\frac{.0082mol}{.320mol/L}

Gives us the answer, in Liters (.0256), which we can then divide by 100 convert to mL.

3 0
3 years ago
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