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77julia77 [94]
4 years ago
10

some ways produce a disturbance and the material they travel through as a result wave travels at a different speed through diffe

rent materials through which of the following would sound waves travel the greatest speed? A the vacuum of a space B the air inside your house C a wooden dining room table or Dthe water inside the swimming pool​
Physics
1 answer:
Gelneren [198K]4 years ago
5 0

Answer:

Underwater or at the pool.

Explanation:

Sound travels 4.3 times faster then on land but you can't hear as well because it becomes distorted, but you can still hear the sound.  

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if you went to the doctor 3 weeks ago && youre going back, will they have to measure your height and weigh you again?
tino4ka555 [31]
No, they usually will not. It also depends why you're going/why you went the first time.
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3 years ago
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What are 2 factors affect air resistance on an object
inessss [21]

friction and the density of the air.

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3 years ago
Apollo 14 astronaut Alan B. Shepard Jr. used an improvised six-iron to strike two golf balls while on the Fra Mauro region of th
Illusion [34]

Complete Question

Apollo 14 astronaut Alan B. Shepard Jr. used an improvised six-iron to strike two golf balls while on the Fra Mauro region of the moon’s surface, making what some consider the longest golf drive in history. Assume one of the golf balls was struck with initial velocity v0 = 32.75 m/s at an angle θ = 32° above the horizontal. The gravitational acceleration on the moon’s surface is approximately 1/6 that on the earth’s surface. Use a Cartesian coordinate system with the origin at the ball's initial position.

Randomized Variables

vo 32.75 m/s

theta 32 degrees

What horizontal distance, R in meters, did this golf ball travel before returning to the lunar surface?

Answer:

The  horizontal distance is  R =  590.2 \ m  

Explanation:

From the question we are told that

 The initial  velocity is  v_o =  32.75 \  m/s

  The angle is  \theta =  26^o

  The gravitational acceleration of the moon is g_m  =  \frac{1}{6}  *  9.8   = 1.633 m/s^2

 Generally the distance traveled is mathematically represented as

    R =  \frac{v_o^2 sin 2(\theta)}{g_m}

=> R =  \frac{32.75^2 sin 2(32)}{1.633}

=> R =  590.2 \ m  

             

8 0
3 years ago
How much work is done when a force of 15.0 newtons is used to lift a box 3.0 meters into the air?
denis-greek [22]

Added potential energy = (mass) x (gravity) x (height)

or

Added potential energy = (weight) x (added height)

If you need to lift a 15N box 3m straight up, you have to increase its potential energy by (15 N) x (3 m) = 45 Joules .

Where is that added potential energy supposed to come from ?  You could use an electric winch, a steam engine, a gasoline-powered motor, thousands of hamsters running on little treadmills that are are connected to the main pulley somehow, or your own arm muscles.  But howEVER you do it, you have to provide <em>45 Joules</em> of WORK in order to increase the potential energy of the box by just that much.  

8 0
3 years ago
Read 2 more answers
A typical running track is an oval with 74-m-diameter half circles at each end. A runner going once around the track covers a di
nirvana33 [79]

Answer:

The acceleration towards the center will be 0.43\ m/s^2

Explanation:

Given the running track is an oval shape, and the diameter of each half-circle is 74 meters.

Also, the runner took 1 minute and 40 seconds to complete 400 m one round of the track.

We need to find the acceleration towards the center.

First, we will find the speed.

v=\frac{d}{t}

Where v is the speed.

d is the distance covered by the rider that is 400 meters.

t is the time taken by the rider to complete the lap which is 1 minute and 40 seconds.  (60\ s +40\ s) = 100 seconds.

So,

v=\frac{400}{100}=4\ m/s

And

a_c=\frac{v^2}{r}

Where a_c is the acceleration towards the center.

r is the radius which will be the half of the diameter 74 meters.

Hence, the radius will be 37 meters.

a_c=\frac{4^2}{37} \\a_c=\frac{16}{37}=0.43\ m/s^2

So, the centripetal acceleration of the rider will be 0.43\ m/s^2

4 0
3 years ago
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