The particles that carry charge through wires in a circuit are mobile electrons. The electric field direction within a circuit is by definition the direction that positive test charges are pushed. Thus, these negatively charged electrons move in the direction opposite the electric field.
Answer:
The distance of m2 from the ceiling is L1 +L2 + m1g/k1 + m2g/k1 + m2g/k2.
See attachment below for full solution
Explanation:
This is so because the the attached mass m1 on the spring causes the first spring to stretch by a distance of m1g/k1 (hookes law). This plus the equilibrium lengtb of the spring gives the position of the mass m1 from the ceiling. The second mass mass m2 causes both springs 1 and 2 to stretch by an amout proportional to its weight just like above. The respective stretchings are m2g/k1 for spring 1 and m2g/k2 for spring 2. These plus the position of m1 and the equilibrium length of spring 2 L2 gives the distance of L2 from the ceiling.
Answer:
The wavelength of these signals is as follow:
- Wavelength of 550 kHz is 545.45 m
- Wavelength of 1600 kHz is 187.5 m
Explanation:
Given that:
Frequency = 550 kHz & 1600 kHz
Velocity = 3.0 x 10⁸ m/s
As we know that frequency is expressed by the following equation:
- Frequency = Velocity / Wavelength ---- (1)
For 550 kHz:
The equation can be rearranged as
Wavelength = Velocity / Frequency
Wavelength = (3.0 x 10⁸ m/s) / (550 x 1000 Hz)
Wavelength = 545.45 m
For 1600 kHz:
Wavelength = Velocity / Frequency
Wavelength = (3.0 x 10⁸ m/s) / (1600 x 1000 Hz)
Wavelength = 187.5 m