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Yanka [14]
3 years ago
11

Show the relation among MA, VR and n.​

Physics
1 answer:
almond37 [142]3 years ago
8 0

Answer:

good luck!!! sorry I just needed the points xoxo

Explanation:

umm yeah no sorry I tried

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Which is a vector quantity speed or velocity
Alecsey [184]
Velocity is a vector quantity. A vector quantity has both a magnitude and a direction. Speed only has a magnitude, but no direction. Velocity has both.
8 0
3 years ago
You have a spring that stretches 0.070 m when a 0.10-kg block is attached to and hangs from it at position y0. Imagine that you
olga nikolaevna [1]

Answer:

a) Δy = 0.144 m

b) W = 0.145 J

c) Us = 0.32 J

d) ymax = 0.144 m

Explanation:

a) First let's find the spring constant using Hooke's Law

F = k*Δy   ⇒  k = F/Δy

where

F = m*g = 0.1 kg*9.81 m/s² = 0.981 N

and  Δy = 0.07 m. Hence

k = 0.981 N/0.07 m = 14.014 N/m ≈ 14 N/m

In order to find the position of the block when we let it go, we need to find the force that caused this expansion in the spring, we know that the reading of the scale was 3 N and this reading includes the force we want to find and the weight of the block, therefore:

f = 3 N - F = 3 N - 0.981 N = 2.019 N

Now that we have found the force we can use Hooke's Law in order to find the position of the block

f = k*Δy   ⇒   Δy = f/k

⇒   Δy = 2.019 N/14 N/m

⇒   Δy = 0.144 m

b) First, notice that there are two kind of potential energy: the potential energy in the spring and the potential energy due to the gravitational field:

W = ΔU

W = ΔUs + ΔUg

W = (Usf - Usi) + (Ugf - Ugi)

Notice that

Us = 0.5*k*y²

where

yf = 0.07 m + 0.144 m = 0.214 m  and

yi = 0.07 m

and we will take the zero level to be the equilibrium position where the block was hanging at rest. Hence

W = 0.5*k*(yf² - yi²) + m*g*(0 - Δy)

⇒ W = 0.5*14 N/m*((0.214 m)² - (0.07 m)²) + (0.1 kg)*(9.81 m/s²)*(0 - 0.144 m)

⇒ W = 0.145 J

c) When we let the block go the spring was stretched by

y = 0.07 m + 0.144 m = 0.214 m

Therefore:

Us = 0.5*k*y²

⇒ Us = 0.5*14 N/m*(0.214 m)²

⇒ Us = 0.32 J

d) Because the position that we pulled the block to it is considered as the amplitude for the vibrational motion that will happen after we release the block, then the maximum height the particle will reach above the equilibrium position is

ymax = Δy = 0.144 m

 

3 0
3 years ago
At which point on this electric field will a test charge show the maximum strength?
Juli2301 [7.4K]

Answer:

A

Explanation:

The figure shows the electric field produced by a spherical charge distribution - this is a radial field, whose strength decreases as the inverse of the square of the distance from the centre of the charge:

E\propto \frac{1}{r^2}

More precisely, the strength of the field at a distance r from the centre of the sphere is

E=k\frac{Q}{r^2}

where k is the Coulomb's constant and Q is the charge on the sphere.

From the equation, we see that the field strength decreases as we move away from the sphere: therefore, the strength is maximum for the point closest to the sphere, which is point A.

This can also be seen from the density of field lines: in fact, the closer the field lines, the stronger the field. Point A is the point where the lines have highest density, therefore it is also the point where the field is strongest.

8 0
3 years ago
A exercise ball is on a table 2.5 m above the ground. What is the mass
horsena [70]

Answer:

2.27kg

Explanation:

The Potential energy gained = Force gravity× Height

Force gravity on the ball is GPE/ height

56.8/2.5=22.72N

the mass = 22.72/10= 2.27kg

4 0
3 years ago
A wave carries___<br> from one place to another.<br> Mechanical waves carry energy through ___
saul85 [17]

Answer:

Energy

A medium

Explanation:

A wave is a disturbance that travels through a medium, transferring energy from one point to another in the medium.

Mechanical waves are waves that require a medium for their propagation.

4 0
3 years ago
Read 2 more answers
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