You have 1 out of 5 chances to get a A in the spinner
<span>You have a 1 out of 6 chances to get a 4 </span>
<span>1/5 times (x) 1/6 = 1/30</span>
Given:

Required:
To write the given equation in slope intercept form.
Explanation:
Consider

Final Answer:
Answer:
![x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]](https://tex.z-dn.net/?f=x%3D%28243%29log_%7B%5Cfrac%7B1%7D%7B81%7D%7D%5B%28%5Cfrac%7B1%7D%7B81%7D%29-1%5D)
Step-by-step explanation:
you have the following formula:

To solve this equation you use the following properties:

Thne, by using this propwerty in the equation (1) you obtain for x
![log_{(\frac{1}{81})}(\frac{1}{81})^{\frac{x}{243}}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\\frac{x}{243}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]](https://tex.z-dn.net/?f=log_%7B%28%5Cfrac%7B1%7D%7B81%7D%29%7D%28%5Cfrac%7B1%7D%7B81%7D%29%5E%7B%5Cfrac%7Bx%7D%7B243%7D%7D%3Dlog_%7B%5Cfrac%7B1%7D%7B81%7D%7D%5B%28%5Cfrac%7B1%7D%7B81%7D%29-1%5D%5C%5C%5C%5C%5Cfrac%7Bx%7D%7B243%7D%3Dlog_%7B%5Cfrac%7B1%7D%7B81%7D%7D%5B%28%5Cfrac%7B1%7D%7B81%7D%29-1%5D%5C%5C%5C%5Cx%3D%28243%29log_%7B%5Cfrac%7B1%7D%7B81%7D%7D%5B%28%5Cfrac%7B1%7D%7B81%7D%29-1%5D)
Given equations are;<span>
2a + 3b = -1 ..................equation 1
3a + 5b = -2 ....................equation 2</span>
Now multiply equation 1 with (-3)
The equation will be;
-6a -9b = 3 …………………..equation 3
Now multiply equation 2 with (2)
The equation will be;
6a + 10b = -4 ……………..equation 4
Now add equation 3 and equation 4
-6a – 9b = 3
<span>6a + 10b = -4</span>
<span>------------------------------</span>
0a + b = -1
b = -1
Now put the value of b in equation 1
2a + 3(-1) = -1
2a -3 = -1
2a = -1+3
2a = 2
a=1
Thus the solution is (a,b) = (1,-1)
<span>
</span>
first off let's notice that the height is 11 meters and the volume of the cone is 103.62 cubic centimeters, so let's first convert the height to the corresponding unit for the volume, well 1 meters is 100 cm, so 11 m is 1100 cm.
![\textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ V=\stackrel{cm^3}{103.62}\\ h=\stackrel{cm}{1100} \end{cases}\implies 103.62=\cfrac{\pi r^2 (1100)}{3} \\\\\\ 3(103.62)=1100\pi r^2\implies \cfrac{3(103.62)}{1100\pi }=r^2 \\\\\\ \sqrt{\cfrac{3(103.62)}{1100\pi }}=r\implies \stackrel{cm}{0.00510199305952} \approx r](https://tex.z-dn.net/?f=%5Ctextit%7Bvolume%20of%20a%20cone%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B%5Cpi%20r%5E2%20h%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20V%3D%5Cstackrel%7Bcm%5E3%7D%7B103.62%7D%5C%5C%20h%3D%5Cstackrel%7Bcm%7D%7B1100%7D%20%5Cend%7Bcases%7D%5Cimplies%20103.62%3D%5Ccfrac%7B%5Cpi%20r%5E2%20%281100%29%7D%7B3%7D%20%5C%5C%5C%5C%5C%5C%203%28103.62%29%3D1100%5Cpi%20r%5E2%5Cimplies%20%5Ccfrac%7B3%28103.62%29%7D%7B1100%5Cpi%20%7D%3Dr%5E2%20%5C%5C%5C%5C%5C%5C%20%5Csqrt%7B%5Ccfrac%7B3%28103.62%29%7D%7B1100%5Cpi%20%7D%7D%3Dr%5Cimplies%20%5Cstackrel%7Bcm%7D%7B0.00510199305952%7D%20%5Capprox%20r)