Answer:
The average speed of the earth in its orbit is 
Explanation:
The average distance between the Earth and the Sun is 
.
The average speed of the earth in its orbit can be found by the next equation :
(1)
Where r is the radius and T is the period.
In this case, the orbit of the Earth can be considered as a circle
(
) instead of an ellipse.
It takes 1 year to the Earth to make one revolution around the Sun. Therefore, its period will be 365.25 days.
Notice that to express the period in terms of seconds, the following is needed:
⇒ 
Then, equation 1 can be used:
Answer: 12,600,000Cm
Explanation:
From the data's;
Charges(q) = 1.8 PC equal to 1.8 x 10^¹²C
Distance = 7 micrometer, is equal to 0.0000070m
From the equation of electric dipole moment, p= q x d, where q= charge, d=distance and p is the dipole moment.
Then we have 1.8x10^¹² x 0.0000070= 12,600,000Cm
NB: The charges are identical.
5m/s
Explanation:
Given parameters:
Mass of ball = 0.1kg
Force on the ball = 5N
time taken = 0.1s
Unknown:
final speed of the ball = ?
Solution:
According to newton's second law "the net force on a body is the product of its mass and acceleration".
Force = mass x acceleration equation 1
Acceleration =
V is the final velocity
U is the initial velocity
T is the time taken
U = O since it is a stationary body;
a = 
Input "a" into equation 1
F = m x
5 = 0.1 x 
V = 5m/s
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Answer:
satellite B
Explanation:
A .F= G (mM)/r²
B .F= G (2mM)/r² = 2G (Mm)r²
C .F= G (3mM)/(2r)² = ¾G (mM)/r²
D .F= G (4mM)/(2r)² = G (mM)/r²
Answer:
Radial acceleration of moon is 
Explanation:
Given :
Time period 
sec
Distance from center of moon to planet 
m
From the equation of radial acceleration,
Where 
So 
Now moon's radial acceleration,
