Work is considered as the Force performed on a body to move it a certain distance, that is
W = Fd
Here
W = Work
F = Force
d = Distance
In this case we have the values of work and distance, therefore clearing for the Force we would have to
Replacing,
Therefore the force that Marissa must exert on the windows shade is 0.4N
Answer:
1) The car is slowing down
2) A = 40N forward & B = 25N up
Explanation:
Whenever you're dealing with forces on moving objects, it is important to look at each of the numbers and the directions they're going in.
With the racecar, we see it has four forces on it, 2,000 N up and down, 8,000 back, and 6,000 N forward. Now, each of these forces are going in their respective directions, but they are most in comparison with the force going in the opposite direction (vertical axis, horizontal axis). The two 2,000 N forces will cancel each other out since there is an equal force in both directions, causing a net force of <u>0 N on the vertical axis</u>. This is because the car is most likely moving on a flat surface. As for the horizontal axis, we simply subtract 6,000 & 8,000 to get a net force of <u>-2,000 N in the backwards direction</u>, telling us that the car is slowing down.
As for the boxes, we see the same vertical and horizontal axes, but separated to each box. Box A has a net force of <u>40 N in the forward direction</u> and Box B has a net force of <u>25 N in the upward direction</u>.
Answer: 2.7 m/s
Explanation:
Given the following :
Period (T) = 8.2 seconds
Radius = 3.5 m
The tangential speed is given as:
V = Radius × ω
ω = angular speed = (2 × pi) / T
ω = (2 × 22/7) / 8.2
ω = 6.2857142 / 8.2
ω = 0.7665505
Therefore, tangential speed (V) equals;
r × ω
3.5 × 0.7665505 = 2.6829268 m/s
2.7 m/s
Answer: 49.92 m
Explanation:
In this situation the following equation will be useful:
Where:
is the final velocity of the car, when it finally stops
is the initial velocity of the car
is the constant acceleration of the car after the driver slams on the brakes
is the stopping distance
Isolating :
