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Orlov [11]
3 years ago
8

You're at rest in a hammock when a hungry mosquito sees an opportunity for lunch. A mild 2 m/s breeze is blowing. If the mosquit

o joins you for lunch it should hover over you by flying
A) against the breeze at 2 m/sB) with the breeze at 2 m/sC) a bit faster than the wind speedD) none of the above
Physics
1 answer:
valentinak56 [21]3 years ago
6 0

Answer:

A) against the breeze at 2 m/s

Explanation:

Given that air is blowing at 2 m/s.An a mosquito eat lunch.If mosquito want to eat lunch he have to move opposite to the direction of air because air is blowing at 2 m/s.So we can say that mosquito have to move against the air.

But in we have to protect our self from mosquito because if any mosquito bite us then it may lead to fever .So the protection is very important from mosquito .

Therefore the answer is --

A

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If the electric potential at a point in space is zero, then the electric field at that point is:
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E - impossible to determine based on the given information
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3 years ago
A solid brass cylinder and a solid wood cylinder have the same radius and mass (the wood cylinder is longer). Released together
Lena [83]

Answer:

a. They will be tie

b. Win the wood cylinder

Explanation:

a.

The both cylinders will reach the bottom at the same time notice the relation in the equation in indepent of the length and both have the same radius and the same rotational inertia.

I=\frac{1}{2}*m*r^2

a=\frac{g*sin(\beta)}{1+I_{com}/m*r^2}

So both will be tie

b.

a_{brass}=\frac{g*sin(\beta)}{1+I_{brass}/m*r^2}=a_{wood}=\frac{g*sin(\beta)}{1+I_{wood}/m*r^2}

The acceleration of the wood cylinder is larger than the acceleration of the brass cylinder so the cylinder of wood will reach the bottom first

a_{brass}

So the wood win the race

6 0
3 years ago
Water enters a baseboard radiator at 180 °F and at a flow rate of 2.0 gpm. Assuming the radiator releases heat into the room at
beks73 [17]

Answer:

Temperature of water leaving the radiator = 160°F

Explanation:

Heat released = (ṁcΔT)

Heat released = 20000 btu/hr = 5861.42 W

ṁ = mass flowrate = density × volumetric flow rate

Volumetric flowrate = 2 gallons/min = 0.000126 m³/s; density of water = 1000 kg/m³

ṁ = 1000 × 0.000126 = 0.126 kg/s

c = specific heat capacity for water = 4200 J/kg.K

H = ṁcΔT = 5861.42

ΔT = 5861.42/(0.126 × 4200) = 11.08 K = 11.08°C

And in change in temperature terms,

10°C= 18°F

11.08°C = 11.08 × 18/10 = 20°F

ΔT = T₁ - T₂

20 = 180 - T₂

T₂ = 160°F

8 0
3 years ago
A giant star has a luminosity of 300 its color is most likely to be
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5 0
3 years ago
Scientific notation of 86400
Mandarinka [93]
8.64×10^4

this is 86400 in scientific notation

3 0
4 years ago
Read 2 more answers
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