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Alekssandra [29.7K]
3 years ago
10

which of the following types of exercise increase lean body mass?. A.) cardiorespiratory fitness. B.) flexibility. C.) muscular

strength and endurance. D.) both a and c
Physics
2 answers:
Sunny_sXe [5.5K]3 years ago
7 0
A lean body mass that the cholesterol level in the body is low and that the excess fats in the body are getting rid off as much as one can. In this case, the exercises  A.) cardiorespiratory fitness such as jogging and <span>C.) muscular strength and endurance such as body building, abs routines are employed. Answer is D. both A and C.</span>
ser-zykov [4K]3 years ago
6 0

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How does friction affect forward motion give an example
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Friction is an opposing force to motion. A car driving fast, slams on the brakes, locking up and the wheels. The car skids to a stop as a result of the friction between the tires and the pavement.
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An object of mass m attached to a spring of force constant k oscillates with simple harmonic motion. The maximum displacement fr
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An object of mass m attached to a spring of force constant k oscillates with simple harmonic motion. The system's potential energy when kinetic energy of (3/4) E is (1/8) k A².

<h3>What is mechanical energy?</h3>

Mechanical energy is the sum of potential energy and kinetic energy.

Total mechanical energy = P.E max = K.E max

Total mechanical energy = K.E +P.E

Given is the kinetic energy is (3/4)E.

E= (3/4)E + P.E

P.E =  (1/4) E

Maximum potential  energy =E = (1/2) k A²

Here. A is the maximum displacement and k is the spring constant.

The potential energy at kinetic energy of (3/4) E is

P.E = (1/4)E = (1/8) k A²

Therefore, the system's potential energy when kinetic energy of (3/4) E is (1/8) k A².

Learn more about mechanical energy.

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6 0
2 years ago
A red light means to stop. If you are turning from a two-way road or onto a two-way road, then you are NOT allowed to turn
lyudmila [28]

A red light means to stop. If you are turning from a two-way road or onto a two-way road, then you are NOT allowed to reverse your car If you can't do it

Red is typically used to indicate danger or warning, and on traffic lights, it indicates a potential hazard ahead and, as a result, serves as a signal for drivers to stop. If the traffic light turns red while you are already at a junction, you must move swiftly to the opposite side to avoid a potential accident with oncoming traffic.
If the traffic light has turned red as you approach the junction and you are just entering it, you must stop. Unless there is a sign clearly telling you not to turn left at the red light, you may do so. Give way to people and cars coming from other directions when turning.

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7 0
2 years ago
Read 2 more answers
Select the statements that describe a vector. Check all that apply.
DerKrebs [107]
By definition, vectors are quantities that have magnitude (positive or negative) and direction.
Graphically, they are illustrated by directed line segments, with arrows that indicate the direction.

Evaluate the given statements.
1. Vectors have a size only.  FALSE
2. Vectors have a size and a direction. TRUE
3. Vectors are indicated with arrows. TRUE
4. Vectors can have only positive values. FALSE
5. Vectors can have positive or negative values. TRUE

3 0
3 years ago
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A moving curling stone, A, collides head on with stationary stone, B. Stone B has a larger mass than stone A. If friction is neg
Kitty [74]

Answer:

The correct answer is option 'c': Smaller stone rebounds while as larger stone remains stationary.

Explanation:

Let the velocity and the mass of the smaller stone be 'm' and 'v' respectively

and the mass of big rock be 'M'

Initial momentum of the system equals

p_i=mv+0=mv

Now let after the collision the small stone move with a velocity v' and the big roch move with a velocity V'

Thus the final momentum of the system is

p_f=mv'+MV'

Equating initial and the final momenta we get

mv=mv'+MV'\\\\m(v-v')=MV'.....i

Now since the surface is frictionless thus the energy is also conserved thus

E_i=\frac{1}{2}mv^2

Similarly the final energy becomes

E_f=\frac{1}{2}mv'^2+\frac{1}{2}MV'^2\

Equating initial and final energies we get

\frac{1}{2}mv^2=\frac{1}{2}mv'^2+\frac{1}{2}MV'^2\\\\mv^2=mv'^2+MV'^2\\\\m(v^2-v'^2)=MV'^2\\\\m(v-v')(v+v')=MV'^2......(ii)

Solving i and ii we get

v+v'=V'

Using this in equation i we get

v'=\frac{v(m-M)}{(M-m)}=-v

Thus putting v = -v' in equation i  we get V' = 0

This implies Smaller stone rebounds while as larger stone remains stationary.

4 0
3 years ago
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