Answer:
because the focal length is negative.
Explanation:
Power of a lens (P) is the reciprocal of its focal length (f).
Answer:
The value of acceleration that accomplishes this is 8.61 ft/s² .
Explanation:
Given;
maximum distance to be traveled by the car when the brake is applied, d = 450 ft
initial velocity of the car, u = 60 mph = (1.467 x 60) = 88.02 ft/s
final velocity of the car when it stops, v = 0
Apply the following kinematic equation to solve for the deceleration of the car.
v² = u² + 2as
0 = 88.02² + (2 x 450)a
-900a = 7747.5204
a = -7747.5204 / 900
a = -8.61 ft/s²
|a| = 8.61 ft/s²
Therefore, the value of acceleration that accomplishes this is 8.61 ft/s² .
For the frequency it is computed by 2 bobs/second which is equal to 2 Hz.Whereas the period is compute by 1/freq = 1/2 secondAnd lastly, the amplitude is the distance from the equilibrium position tot he maximum displacement so in this case, it is one half the 25 cm peak to peak distance, or 12.5 cm.