Answer:
B
Explanation:
From Newton's law of motion, we have:
V^2 = U^2 + 2gH
Where V and U are final and initial velocity respectively.
H is the height.
For the object to have a sustain a maximum height it means the final velocity of the object is zero.
By computing the height of the object sustain by A, we have:
0^2 = 2^2 -2×10×H
0= 4 -20H
4 = 20H;
H= 0.2m
For object B we have;
0^2 = 1^2 -2×10×H
0 = 1 -20H
H = 1/20= 0.05m
From computing the height sustain by both objects, we see object B is projected at a shorter height into atmosphere than A.
Hence object B will return to the ground first.
Answer:
the smallest angle from the antennas is <em>47.3°</em>
Explanation:
We first need to write the expression for the relation between the wavelength (λ) and the frequency (f) of the wave, and then solve for the wavelength.
Therefore, the relation is:
λ = c /f
where
- c is the speed of light constant
- λ is the wavelength
- f is the frequency
Thus,
λ = (3 × 10⁸ m/s) / (3.4 MHz)
= (3 × 10⁸ m/s) / (3.4 MHz)(10⁶ Hz/1 MHz)
= 88.235 m
Therefore, the smallest angle measured (from the north of east) from the antennas for the constructive interference of the two-radio wave can be calculated as
θ = sin⁻¹(λ / d)
where
- d is the distance between the two radio antennas
Thus,
θ = sin⁻¹(88.235 / 120)
<em>θ = 47.3 °</em>
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Therefore, the smallest angle from the antennas, measured north of east, at which constructive interference of two radio waves occurs is <em>47.3 °</em>.
Answer:

Explanation:
Knowing that the formula for average velocity is:

Being said that, we know that the person's displacement is zero because it returns to its starting point

That means 

Answer:
<em>The average acceleration of the object is 0.5 cm/s^2</em>. Answer: A)
Explanation:
<u>Average Acceleration</u>
The average acceleration of a moving object is the rate at which the speed changed over time in a specific period. It can be calculated as follows:

Where vf is the final speed, vo is the initial speed and t is the time.
The speed-time shows the speed starts at 0 cm/s and ends at 4 cm/s over the 8 seconds period. The average acceleration is:

The average acceleration is 0.5 cm/s^2
A) Correct. The average acceleration is 0.5 cm/s^2
B) Incorrect. The average acceleration is 0.5 cm/s^2
C) Incorrect. The average acceleration is 0.5 cm/s^2
D) Incorrect. The average acceleration is 0.5 cm/s^2