Answer:
Explanation:
The movement of a body can be analyzed using New's first law. In an inertial frame (without acceleration) every body is kept at rest or moving at constant speed until there is an external force that changes this state
Let's analyze these cases in the framework of this first law
a) If the vehicle is going at constant speed the two bodies (the egg and the hands) do not change movement so he had returned to the hands
b) If the vehicle accelerates the passenger goes faster, but the egg that is not subject to anything does not change the movement, so it falls behind the passenger
c) If the vehicle slows down, the passenger reduces its speed and the distance traveled in time, but the egg that is not attached follows its movement and falls in front of the passenger.
There are two types of electric charges; positive and negative
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Answer:
The tension in string is found to be 188.06 N
Explanation:
For the vibrating string the fundamental frequency is given as:
f1 = v/2L
where,
f1 = fundamental frequency = 335 Hz
v = speed of wave
L = length of string = 28.5 cm = 0.285 m
Therefore,
v = f1 2L
v = (335 Hz)(2)(0.285)
v = 190.95 m/s
Now, for the tension:
v = √T/μ
v² = T/μ
T = v² μ
where,
T = Tension
v = speed = 190.95 m/s
μ = linear mass density of string = mass/L = 0.00147 kg/0.285 m = 5.15 x 10^-3 kg/m
Therefore,
T = (190.95 m/s)²(5.15 x 10^-3 kg/m)
<u>T = 188.06 N</u>
The goalkeeper at his goal cannot kick a soccer ball into the opponent’s goal without the ball touching the ground
Explanation:
Consider the vertical motion of ball,
We have equation of motion v = u + at
Initial velocity, u = u sin θ
Final velocity, v = 0 m/s
Acceleration = -g
Substituting
v = u + at
0 = u sin θ - g t

This is the time of flight.
Consider the horizontal motion of ball,
Initial velocity, u = u cos θ
Acceleration, a =0 m/s²
Time,
Substituting
s = ut + 0.5 at²

This is the range.
In this problem
u = 30 m/s
g = 9.81 m/s²
θ = 45° - For maximum range
Substituting

Maximum horizontal distance traveled by ball without touching ground is 45.87 m, which is less than 95 m.
So the goalkeeper at his goal cannot kick a soccer ball into the opponent’s goal without the ball touching the ground
Answer:
955.5N
Explanation:
The normal force is given by the difference between the centripetal force and gravity at the top of the loop:

mass m = 65kg
radius of the loop r = 4m
velocity v = ?
g = 9.8 m/s²
To find the centripetal force, you need to find the velocity of the car at the top of the loop.
Use energy conservation:

At the top of the hill:

At the top of the loop:

Setting both energies equal and canceling the mass m gives:

Solving for v:

Using v in the first equation:
