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kaheart [24]
4 years ago
5

A light bulb does 100 joules of work in 2.5 seconds. how much work power dos it have

Physics
1 answer:
Lesechka [4]4 years ago
5 0
100/2.5 because power=energy/time
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(2) Put 5kg mass at left side (at 2m). This is fixed throughout the experiment! (3) Try to balance by putting 5kg mass at the ri
dmitriy555 [2]

We can conclude that as the mass on the right increases, the distance of the mass towards the right decreases. Also when the two masses balance, the net torque is zero.

<h3>What is torque</h3>

The torque experienced by an object a given position is the product of the applied force and the perpendicular distance of the object.

When 5 kg mass is at 2 m on the left, another 5 kg at 2 m on the right will balance it.

\tau _{net} = (2 \times 5 \times 9.8)  - (2 \times 5 \times 9.8)\\\\\tau _{net} = 0

<h3>Position of 10 kg mass on the right</h3>

Apply principle of moment

F_1r_1 = F_2r_2\\\\(m_1gr_1) = (m_2gr_2)\\\\r_2 = \frac{m_1gr_1}{m_2g} \\\\r_2 = \frac{m_1 r_1}{m_2} \\\\r _2 = \frac{5 \times 2}{10} \\\\r_2 = 1 \ m

<h3>Net torque</h3>

\tau_{et} = m_2gr_2 - m_1gr_1\\\\\tau_{et} = (10 \times 9.8 \times 1) - (5 \times 9.8 \times 2)\\\\\tau_{et} = 0

<h3>Position of the 20 kg mass</h3>

r_2 = \frac{5 \times 2}{20} \\\\r_2 = 0.5 \ m

<h3>Net torque</h3>

\tau_{et} = m_2gr_2 - m_1gr_1\\\\\tau_{et} = (20 \times 9.8 \times 0.5) - (5 \times 9.8 \times 2)\\\\\tau_{et} = 0

Thus, we can conclude that as the mass on the right increases, the distance of the mass towards the right decreases. Also when the two masses balance, the net torque is zero.

Learn more about principles of moment here: brainly.com/question/26117248

7 0
2 years ago
A visitor to a lighthouse wishes to determine the height of the tower. She ties a spool of thread to a small rock to make a simp
masha68 [24]

To solve this problem we must rely on the equations of the simple harmonic movement that define the period as a function of length and gravity as

T = 2\pi \sqrt{\frac{l}{g}}

Where

l = Length

g = Gravity

Re-arrange to find L,

L = g (\frac{T}{2\pi})^2

Our values are given as

g = 9.81m/s

T = 10.1s

Replacing,

L = g (\frac{T}{2\pi})^2

L = (9.81) (\frac{10.1}{2\pi})^2

L = 25.348m

Therefore the height would be 25.348m

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Katena32 [7]

Answer:

What is the question

Explanation:

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E mirror.<br>w<br>WWW<br>+<br>9<br>の<br>10 V​
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Explanation:

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Dale skis down a hill with a slope of 30°. Given that there is friction acting
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The answer is A.

Explanation:

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