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9966 [12]
3 years ago
6

What term generally describes small chunks of rocks and debris in space? PLEAS HURRY!

Physics
2 answers:
yan [13]3 years ago
4 0
B or meteors so yeanfjfjf
Brilliant_brown [7]3 years ago
4 0

Answer:

B) meteoroids.  The key word here is "generally."  Not when it enters the atmosphere or hits the surface of the Earth.  

Explanation:

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We move a square loop of wire 2.3 cm on a side into a region of uniform magnetic field of 1.5 T with the plane of the loop perpe
vova2212 [387]

Answer:

Force will be F=8.33\times 10^{-4}N

Explanation:

We have given side of wire d = 2.3 cm = 0.023 m

Magnetic field B = 1.5 T

Velocity v = 2.1 m/sec

Resistance R = 3 ohm

We know that current is given by i=\frac{Bvd}{R}=\frac{1.5\times 2.1\times 0.023}{3}=0.02415A

Power is given by P=i^2R=0.02415^2\times 3=0.00174watt

We know that power is also given by P=Fv

So 0.00174=F\times 2.1

F=8.33\times 10^{-4}N

4 0
3 years ago
A ball at rest rolls across a frictionless floor at 12.0 m/s/s. How far will it travel in
professor190 [17]

Answer:

The distance, d travelled by the ball is 768 metres.

Explanation:

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of final speed from the initial speed all over time.

Hence, if we subtract the final speed from the initial speed and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{initial \; speed  -  final \; speed}{time}

a = \frac{v  -  u}{t}

Where,

a is acceleration measured in ms^{-2}

v and u is initial and final speed respectively, measured in ms^{-1}

t is time measured in seconds.

Given the following data;

Acceleration = 12.0m/s²

Time, t = 8secs

Velocity =?

First, we would calculate its velocity;

a = \frac{v  -  u}{t}

Since the ball rolls at rest, initial velocity is zero (0).

V = a * t

V = 12 * 8

Velocity = 96ms^{-1}

We can now solve for the distance;

Velocity = \frac{distance}{time}

Therefore,

Distance = velocity * time

Distance = 96 * 8

Distance = 768m.

3 0
3 years ago
Plzz answer this question correctly
Leno4ka [110]

Answer:

by reducing friction.....

6 0
3 years ago
A object of mass 33 is dropped from a height of 85 meters. Calculate the average power developed by the object in falling throug
DochEvi [55]
Power  =  Work done  /  Time taken.

Work done =  mgh
Mass, m = 33kg    ( Am presuming it is 33 kg).
h =  85 m.
Work done =  33 * 9.81* 85 =  27517.05  J.

Time taken.
Since object was dropped from height, it fell under gravity.
Using    H =  ut  +  (1/2) * gt^2.              u = 0.
               H =  1/2 gt^2.
               t  =   (2H/g) ^ (1/2)
               t  =  (2*85/9.81) ^ 0.5 =  4.1628 s.

Power  =    27517.05 / 4.1628 = 6610.23 Watts.
             =  6610 W  to  3 S. f.

3 0
3 years ago
How is it possible for the same object to have different amounts of gravitational potential energy?
Arlecino [84]

Answer:

In Newtonian mechanics, the gravitational energy possessed by a mass, because of the gravitational field produced by a second mass.

Explanation:

8 0
3 years ago
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