The force which has the greatest effect on causing this object to slow while it remains in contact with the ramp is: B. a frictional force.
<h3>What is a force?</h3>
A force can be defined as a push or pull of an object or physical body, which typically results in a change of motion (acceleration), especially due to the interaction of the object with another.
<h3>The types of force.</h3>
In Science, there are different types of force and these include the following:
<h3>What is a
frictional force?</h3>
Friction force can be defined as a type of force that resists and slows the relative motion of two physical objects when there surfaces come in contact. This ultimately implies that, a frictional force prevents two surfaces from easily sliding over or slipping across one another.
In this context, we can infer and logically deduce that the force which has the greatest effect on causing this object to slow while it remains in contact with the ramp is a frictional force.
Read more on frictional force here: brainly.com/question/25253774
#SPJ1
Complete Question:
Brandon pushes an object on a ramp as shown in the diagram.
While Brandon pushes the object and it remains in contact the ramp, which force has the greatest effect on causing it to slow?
A. the applied force
B. a frictional force
C. the force due to gravity
D. a force of air resistance
Answer:
point-contact transistors
From largest to smallest- atom, nucleus, proton and electron
Answer:
The answer is a=b=c=3.833 cm
Explanation:
Lets call the variables a=side a b=side b c=side c
We have that the formula of the equilateral triangle for its height is:
1)h=(1/2)*root(3)*a
2) If we resolve the equation we have
2.1)2h=root(3)*a
2.2)(2h/root(3))=a
3) After the replacement of each value we have that
a=2*3.32/1.73205
a=3.833 cm
And we know that the equilateral triangle has the same value for each side so a=b=c=3.833 cm
The power source voltage remains the same in a parallel circuit,
And we'll have equal current in both lines
<h3>Kirchhoff's junction rule</h3>
Generally, Kirchhoff's junction rule states that when there is current flow at any junction of a circuit, the total sum of this current rushing into the junction amount to the same amount of current out of the Node.
Therefore, when the parallel circuit has two branches
i=i1+12
Since we have an equal resistor therefore we'll have equal current in both lines i.e i1=i2
And Voltage remains the same in a parallel circuit
More on Voltage
brainly.com/question/14883923