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Juliette [100K]
3 years ago
9

W/5=3 what does w equal

Mathematics
2 answers:
m_a_m_a [10]3 years ago
7 0

Answer:

w=15

Step-by-step explanation:

w/5=3

multiply by 5 on both sides

w=3*5

∴ w=15

xz_007 [3.2K]3 years ago
7 0

Answer:

15

Step-by-step explanation:

If something over 5 is 3, that means w divided by 5 equals 3.

That can bve translated to W=3 times 5, which is 15.

Therefore, W= 15.

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Please help, will give brainliest!<br>(please explain how as well)​
vovikov84 [41]

Answer:

C

Step-by-step explanation:

Since GJ bisects ∠ FGH , then ∠ FGJ = ∠ JGH = x + 14

∠ FGH = ∠ FGJ + ∠ JGH , substitute values

4x + 16 = x + 14 + x + 14 = 2x + 28 ( subtract 2x from both sides )

2x + 16 = 28 ( subtract 16 from both sides )

2x = 12 ( divide both sides by 2 )

x = 6

Thus

∠ FGJ = x + 14 = 6 + 14 = 20° → C

4 0
2 years ago
The horizontal axis in the sampling distribution of ModifyingAbove p with caret represents all possible sample proportions from
lora16 [44]

Answer: (a). 99 percent of the sample proportions results in a 99% confidence interval that includes the population proportion.

(b). 1 percent of the sample proportions results in a 99% confidence interval that does not include the population proportion.

Step-by-step explanation:

(a). 99 percent of the sample proportions results in a 99% confidence interval that includes the population proportion.

Explanation: If multiple samples were drawn from the same population and a 99% CI calculated for each sample, we would expect the population proportion to be found within 99% of these confidence intervals.

(b). 1 percent of the sample proportions results in a 99% confidence interval that does not include the population proportion.

Explanation: The 99% of the confidence intervals includes the population proportion value, it means, the remaining (100% – 99%) 1% of the intervals does not includes the population proportion.

If multiple samples were drawn from the same population and a 99% CI calculated for each sample, we would expect the population proportion to be found within 99% of these confidence intervals and 1 percent of the sample proportions results in a 99% confidence interval that does not include the population proportion.

5 0
3 years ago
A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0
2 years ago
Read 2 more answers
4^-2 what does this equal
S_A_V [24]

0.0625

or 16 im not sure

4 0
3 years ago
Read 2 more answers
67.1 minus 38.29 = <br> A. -105.39 <br> B. 28.81 <br> C. -28.81 <br> D. -44.352
zalisa [80]
67,1 - 38,29 = 28,81

B

5 0
3 years ago
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