The kinetic energy K given to the helium nucleus is equal to its potential energy, which is

where q=2e is the charge of the helium nucleus, and

is the potential difference applied to it.
Since we know the kinetic energy, we have

and from this we can find the potential difference:
This is simple as power in watts is equal to joules per second so we can do 1500 joules divided by 30 seconds which equals 50 watts
The lord of the greeks answer d
Answer:
Fr^2 = 75.9N+105.8N=181.7
<u><em>Fr = </em></u><u><em>181.7N.</em></u>