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3 years ago

Consider the combustion of carbon monoxide (CO) in

Chemistry

1 answer:

Julli [10]3 years ago

6 0

Answer:

3.60 mol CO₂

Explanation:

Balanced chemical reaction:

2CO + O₂ ⇒ 2CO₂

The molar ratio between CO₂ and CO is 1:1

2CO₂/2CO = CO₂/CO

Thus, the moles of CO₂ produced from 3.60 moles of CO is 3.60 moles:

(3.60 mol CO)(CO₂/CO) = 3.60 mol CO₂

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All cells in living organisms undergo cellular respiration. The chemical reaction for cellular respiration is stated below. (Glu

Ne4ueva [31]

Answer : The total mass of carbon dioxide and water produced will be, 65.7 grams.

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

$C_6H_{12}O_6+6O_2\rightarrow 6CO_2+6H_2O$

According to the law of conservation of mass,

Total mass of reactant side = Total mass of product side

Total mass of $C_6H_{12}O_6+6O_2$ = Total mass of $6CO_2+6H_2O$

As we are given :

Total mass of $C_6H_{12}O_6+6O_2$ = 65.7 grams

So,

65.7 grams = Total mass of $6CO_2+6H_2O$

Therefore, the total mass of carbon dioxide and water produced will be, 65.7 grams.

4 0

3 years ago

Please help I just need those last 4! :)

mojhsa [17]

Answer:

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3. Thermistor

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1. ???

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5 0

3 years ago

Explain how the sodium chloride works as a preservative

Olegator [25]

Answer:

Eg:Salt...Essentially, water moves across a cell membrane to try to equalize the salinity or concentration of salt on both sides of the membrane. If you add enough salt, too much water will be removed from a cell for it to stay alive or reproduce. A high concentration of salt kills organisms that decay food and cause disease.

Explanation:

8 0

3 years ago

PLEASE HELP WILL MARK BRAINLIEST ! Where did the mass of the forest trees come from? What happens to that mass when the forest b

Oxana [17]

Answer:

it is a flat mass

Explanation:

Because it was used up.

3 0

3 years ago

The depletion of ozone (O3) in the stratosphere has been a matter of great concern among scientists in recent years. It is belie

Deffense [45]

Answer: Nitric oxide is the limiting reagent. The number of moles of excess reagent left is 0.0039 moles. The amount of nitrogen dioxide produced will be 0.7912 g.

Explanation:

To calculate the number of moles, we use the equation

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

For ozone:

Given mass of ozone = 0.827 g

Molar mass of ozone = 48 g/mol

Putting values in above equation, we get:

$\text{Moles of ozone}=\frac{0.827g}{48g/mol}=0.0172mol$

For nitric oxide:

Given mass of nitric oxide = 0.635 g

Molar mass of nitric oxide = 30.01 g/mol

Putting values in above equation, we get:

$\text{Moles of nitric oxide}=\frac{0.635g}{30.01g/mol}=0.0211mol$

For the given chemical equation:

$O_3+NO\rightarrow O_2+NO_2$

By Stoichiometry of the reaction:

1 mole of ozone reacts with 1 mole of nitric oxide.

So, 0.0172 moles of ozone will react with = $\frac{1}{1}\times 0.0172=0.0172moles$ of nitric oxide

As, given amount of nitric oxide is more than the required amount. So, it is considered as an excess reagent.

Thus, ozone is considered as a limiting reagent because it limits the formation of product.

Amount of excess reagent (nitric oxide) left = 0.0211 - 0.0172 = 0.0039 moles

By Stoichiometry of the reaction:

1 mole of ozone produces 1 mole of nitrogen dioxide.

So, 0.0172 moles of ozone will react with = $\frac{1}{1}\times 0.0172=0.0172moles$ of nitrogen dioxide

Now, calculating the mass of nitrogen dioxide from equation 1, we get:

Molar mass of nitrogen dioxide = 46 g/mol

Moles of nitrogen dioxide = 0.0172 moles

Putting values in equation 1, we get:

$0.0172mol=\frac{\text{Mass of nitrogen dioxide}}{46g/mol}\\\\\text{Mass of nitrogen dioxide}=0.7912g$

Hence, nitric oxide is the limiting reagent. The number of moles of excess reagent left is 0.0039 moles. The amount of nitrogen dioxide produced will be 0.7912 g.

8 0

3 years ago