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marta [7]
3 years ago
9

Due to efficiency considerations related to its bow wake, the supersonic transport aircraft must maintain a cruising speed that

is a constant ratio to the speed of sound (a constant Mach number).
If the aircraft flies from warm air into colder air, should it increase or decrease its speed? Explain.
Physics
1 answer:
givi [52]3 years ago
7 0

Answer:

decreases.

Explanation:

When the aircraft is flies from the warm air into the  colder air then its speed will be decreases.

as we know that

we know mach number is constant  

so that here Mach number M is expressed as  

M = \frac{u}{v}      .............................1

here u is  Local flow velocity with respect to the boundarie and v is the speed of sound in the medium

If the aircraft flies from hot air to cold air, the speed of sound in the medium will decrease. But the Mach number remains constant. Therefore, the local flow velocity relative to the boundaries also decreases.

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If you start rolling down this hill, your potential energy will be converted to kinetic energy. At the bottom of the hill ypu KE
Serjik [45]

Answer:

v=\sqrt{(2x/m)}\  \ m/s

Explanation:

Potential Energy= Kinetic Energy

Let x be the value of Kinetic Energy.

We know that

PE=KE=x\\x=\frac{1}{2}mv^2\\

Make v the subject of the formula to get speed at the bottom of the hill.

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3 years ago
What's the difference between a wavelength and an an amplitude?
valkas [14]
Wavelength - the distance from one wave crest or trough to another wave crest or trough. Amplitude - the distance from the median point or "middle" of the wave straight up to a crest (a maximum) or straight down to a trough (or minimum), which is the peak amplitude; or the distance from a trough straight up to a crest, or a crest straight down to a trough, called peak-to-peak amplitude.
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4 years ago
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A .5 kg air puck moves to the right at 3 m/s, colliding with a 1.5kg air puck that is moving to the left at 1.5 m/s.
arlik [135]

Answer:

part (a) v = 1.7 m/s towards right direction

part (b) Not an elastic collision

part (c) F = -228.6 N towards left.

Explanation:

Given,

  • Mass of the first puck = m_1\ =\ 5\ kg
  • Mass of the second puck = m_2\ =\ 3\ kg
  • initial velocity of the first puck = u_1\ =\ 3\ m/s.
  • Initial velocity of the second puck = u_2\ =\ -1.5\ m/s.

Part (a)

Pucks are stick together after the collision, therefore the final velocities of the pucks are same as v.

From the conservation of linear momentum,

m_1u_1\ +\ m_2u_2\ =\ (m_1\ +\ m_2)v\\\Rightarrow v\ =\ \dfrac{m_1u_1\ +\ m_2u_2}{m_1\ +\ m_2}\\\Rightarrow v\ =\ \dfrac{5\times 3\ -\ 1.5\times 1.5}{5\ +\ 1.5}\\\Rightarrow v\ =\ 1.7\ m/s.

Direction of the velocity is towards right due to positive velocity.

part (b)

Given,

Final velocity of the second puck = v_2\ =\ 2.31\ m/s.

Let v_1 be the final velocity of first puck after the collision.

From the conservation of linear momentum,

m_1u_1\ +\ m_2u_2\ +\ m_1v_1\ +\ m_2v_2\\\Rightarrow v_1\ =\ \dfrac{m_1u_1\ +\ m_2u_2\ -\ m_2v_2}{m_1}\\\Rightarrow v_1\ =\ \dfrac{5\times 3\ -\ 1.5\times 1.5\ -\ 1.5\times 2.31}{5}\\\Rightarrow v_1\ =\ 1.857\ m/s.

For elastic collision, the coefficient of restitution should be 1.

From the equation of the restitution,

v_1\ -\ v_2\ =\ e(u_2\ -\ u_1)\\\Rightarrow e\ =\ \dfrac{v_1\ -\ v_2}{u_2\ -\ u_1}\\\Rightarrow e\ =\ \dfrac{1.857\ -\ 2.31}{-1.5\ -\ 3}\\\Rightarrow e\ =\ 0.1\\

Therefore the collision is not elastic collision.

part (c)

Given,

Time of impact = t = 25\times 10^{-3}\ sec

we know that the impulse on an object due to a force is equal to the change in momentum of the object due to the collision,

\therefore I\ =\ \ m_1v_1\ -\ m_1u_1\\\Rightarrow F\times t\ =\ m_1(v_1\ -\ u_1)\\\Rightarrow F\ =\ \dfrac{m_1(v_1\ -\ u_1)}{t}\\\Rightarrow F\ =\ \dfrac{5\times (1.857\ -\ 3)}{25\times 10^{-3}}\\\Rightarrow F\ =\ -228.6\ N

Negative sign indicates that the force is towards in the left side of the movement of the first puck.

3 0
3 years ago
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NeX [460]

Answer:

In positive feedback mechanism, the output is fed back to the system which further increases the output. Hence, it is known as positive feedback because it amplifies the output.

In the negative feedback mechanism, the output is fed back to the system which further decreases the the output. Hence, it is known as negative feedback because it reduces the output.

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long, straight, vertical wire carries a current upward. Due east of this wire, in what direction does the magnetic field point?
Kamila [148]

Answer:

The correct answer to the question is;

North

Explanation:

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Therefore, since the direction of the current is upward and a force is acting with a direction towards the east of the wire then the direction of the magnetic field is northwards.

6 0
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