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Monica [59]
4 years ago
10

A train increase its speed steadily from 10m/s to 20m/s in 1minutes A what is the average speed during this time in m/s B how fa

r does it travel while increasing its speed
Physics
1 answer:
Ipatiy [6.2K]4 years ago
3 0

If it increased its speed steadily at a constant rate, then the average speed for the minute was

(1/2)(10m/s + 20m/s) = 15 m/s .

Rolling at an average speed of 15 m/s for 1 minute (60 seconds), it travels

(15 m/s) (60 sec) = 900 meters

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A car is traveling to the right with a speed of 2.0 m/s on an icy road when the brakes are applied. The car begins sliding with
quester [9]

Answer:

t = 3.0s

Explanation:

U = 2.0m/s , V = 0 (stop) , S = 3m , t =?

From V^2 - U^2 = 2aS

=) a = -4/6 = -0.667m/s^2

Now again by V-U = at

We have t = -U/a = 2/0.667 = 3s

Required time is t = 3.0s

6 0
3 years ago
What is motion? give 3 examples
Tomtit [17]

Answer:

Motion definition: the action or process of moving or being moved.

Examples:

1. moving a hand

2. riding a bicycle

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8 0
3 years ago
Calculate the kinetic energy of a 4 kg object traveling at 16 m/s
melisa1 [442]
To work out kinetic energy, we use the following formula: KE = 0.5 x mv^2. So, 0.5 x 4 x 16^2 = 512 J
6 0
3 years ago
Two one-coulomb point charges are at a distance of 1.67 m from each other. What is the size of the electric force between the tw
pychu [463]

Explanation:

The given data is as follows.

       distance (r) = 1.67 m

     q_{1} = q_{2} = 1 C

It is known that formula for electric force between two charges is as follows.

          F = \frac{kq_{1} \times q_{2}}{r^{2}}

Hence, putting the given values into the above formula as follows.

       \frac{9 \times 10^{9} \times 1 \times 1}{(1.67)^{2}}

            = 3.227 \times 10^{9}

As it is given that mass of  Falcon Heavy rocket is 1421. Therefore, weight of 1 Falcon rocket is as follows.

       weight of 1 falcon rocket = 142 \times 10^{3} \times 9.8

Therefore, number of falcon rockets will be calculated as follows.

         No. of falcon rockets = \frac{3.227 \times 10^{9}}{142000 \times 9.8}

                              = 2.31897 \times 10^{3}

                              = 2318.9 falcons

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5 0
3 years ago
A car travels at a constant speed around a circular trackwhose
Mashutka [201]

Answer:

a = 0.77 m/s^2

Explanation:

The centripetal acceleration is given as

a = \frac{v^2}{R}

The velocity of the car can be calculated using the circumference of the track and the period of the car.

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So, the acceleration is

a = \frac{45^2}{2.6\times 10^3} = 0.77~m/s^2

8 0
4 years ago
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