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makvit [3.9K]
3 years ago
12

R: Law of Conservation of Energy Pre-Write

Physics
1 answer:
Bad White [126]3 years ago
3 0

Answer:

V at C is 3.6 m/s

Explanation:

At A kinetic energy is zero and potential energy=mgh=0.5*9.81*0.6=2.943 J

By conservation of energy.

KE+PE=Constant

At C PE=0.6 J

the KE=2.943-0.6=2.343 J

KE=0.5*m*v^2

v=√[KE/(0.5*m)]=3.06 m/s

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What is the number N0 of 99mTc atoms that must be present to have an activity of 15mCi?
svetoff [14.1K]
Base on my research, within 2 hours you have a number of atoms which remain. 
N= N0*2^(-t/6.020 = N= N0*2^-0.33223= 07943 N0

So, the number of atoms that are being disintegrated is N0-N=N0*(1-0.79430)=0.2057 N0

It must be equal to 15 mCi = 15*3.7*10^7= 5.55*10^8 atoms 

N0= 5.55*10*8/0.2057  = 2.698*10^9 atoms

Therefore, 2.698*10^9 atoms is the number of N0
4 0
3 years ago
A car jumps off a ramp with a Kinetic energy of 5,000 joules. This same car has a gravitational potential energy of 4,685 joules
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Answer:

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Explanation:

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Hence, the car's total mechanical engery is equal to 14,653 J.

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Which list shows the development of atomic models in chronological order?
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7 0
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Four long parallel wires each carry 2.0 A in the same direction. They are parallel to the z-axis, and they pass through the corn
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