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ValentinkaMS [17]
3 years ago
12

Two identical objects in outer space have a head-on collision and stick together. If, before the collision, one had been moving

at 2 m/s and the other at 1 m/s, their combined speed after the collision would be?
Physics
1 answer:
julia-pushkina [17]3 years ago
5 0

Answer:

1.5 m/s

Explanation:

Momentum is conserved and conservation of momentum is

p₁ + p₂ = p'₁ + p'₂

or

m₁v₁ + m₂v₂ = m₁v'₁  + m₂v'₂

In our problem, after collision v'₁ will be equal to v'₂.

Since objects are identical m₁ = m₂

m(v₁+ v₂) = 2m x v'₁

(2m/s + 1m/s) = 2v'₁

v'₁ = v'₂ = 1.5 m/s

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8_murik_8 [283]

Answer:

The transverse component of acceleration is 26.32 m/s^2 where as radial the component of acceleration is 8.77 m/s^2

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As per the given data

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Here

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So

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a_r=r''-r\theta'^2

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The radial component of acceleration is 8.77 m/s^2

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5 0
3 years ago
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Ronch [10]
B when the ball is at its maxium height 
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