Answer:
v = 3 m/s
Explanation:
P is the momentum
m is the mass
v is the velocity
P = m•v
300 = 100•v Divide both sides per 100
300/100 = v
v = 3 m/s
Answer:
285 seconds
Explanation:
Jenny speed is 3.8 m/s
Alyssa speed in 4.0 m/s
Alyssa starts after 15 seconds
Find the distance covered by Jenny, when Alyssa starts
Distance=Speed*time
Distance covered by Jenny in 15 seconds= 3.8×15=57m
Relative speed of the two members heading same direction will be;
4.0m/s-3.8m/s=0.2m/s
To find the time Alyssa catch up with Jenny you divide the distance to be covered by Alyssa by the relative speed of the two
Distance=57m, relative speed=0.2m/s t=57/0.2 =285 seconds
=4.75 minutes
Answer:
The spring constant of the spring is 205.42 N/m.
Explanation:
Springs have their own natural "spring constants" that define how stiff they are. The letter k is used for the spring constant, and it has the units N/m.
k = -F/x
The period of a spring-mass system is proportional to the square root of the mass and inversely proportional to the square root of the spring constant.
Given:
mass of object in SHM = m = 0.30 kg
Time period of the spring mass system = 0.24s
Spring constant = k ?
Finding 'k' using Time period 'T':
We know that
Answer:
kinetic energy will be equal to 0
Explanation:
this is because at final position velocity of body will become zero.
kinetic energy eill be 8 times
Answer:
False
Explanation:
When the location of the poles changes in the z-plane, the natural or resonant frequency (ω₀) changes which in turn changes the damped frequency (ωd) of the system.
As the poles of a 2nd-order discrete-time system moves away from the origin then natural frequency (ω₀) increases, which in turn increases damped oscillation frequency (ωd) of the system.
ωd = ω₀√(1 - ζ)
Where ζ is called damping ratio.
For small value of ζ
ωd ≈ ω₀
