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WITCHER [35]
3 years ago
11

Two diverging light rays, originating from the same point, have an angle of 5° between them. After the rays reflect from a plane

mirror, what is the angle between them? Construct one possible ray diagram that supports your answer.

Physics
2 answers:
Alexeev081 [22]3 years ago
4 0

Answer:

5°  

Explanation:

Two diverging light rays, originating from the same point, have an angle of 5° between them.

According to laws of reflection the angle of incidence is equal to the angle of reflection.

From the attached figure, it is clear that the after reflection from a plane mirror the angle between two rays will be 5°.

O be the originating point. m and n two diverging light rays. When they strikes at the plane mirror, the laws of reflection still fulfilled.

LuckyWell [14K]3 years ago
3 0
As a reference, consider the line from the point perpendicular to the mirror.
That direction is called 'normal' to the mirror.

The ray on the right leaves the point traveling 5° to the right of the normal,
and leaves the mirror on a path that's 10° to the right of the normal.

The ray on the left leaves the point traveling 5° to the left of the normal,
and leaves the mirror on a path that's 10° to the left of the normal.

The angle between the two rays after they leave the mirror is 20° .

Frankly, Charlotte, if there were more than 5 points available for this answer,
I'd seriously consider giving you a drawing too.
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Why is deforestation a serious global environment problem
julia-pushkina [17]

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Explanation:

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When one member of a binary star system is a black hole, and astronomers detect flickering x-rays coming from the system, where
puteri [66]

When one member of a binary star system is a black hole, and astronomers detect flickering x-rays coming from the system, these x-rays usually coming from a disk of material around the black hole (material that has been pulled from the companion star and is falling toward the black hole).

A binary black hole (BBH) is a system consisting of two black holes in close orbit around each other. Like black holes themselves, binary black holes are often divided into stellar binary black holes, formed either as remnants of high-mass binary star systems or by dynamic processes and mutual capture; and binary supermassive black holes, believed to be a result of galactic mergers.

For many years, proving the existence of binary black holes was made difficult because of the nature of black holes themselves and the limited means of detection available.

However, in the event that a pair of black holes were to merge, an immense amount of energy should be given off as gravitational waves, with distinctive waveforms that can be calculated using general relativity.

Therefore, during the late 20th and early 21st century, binary black holes became of great interest scientifically as a potential source of such waves and a means by which gravitational waves could be proven to exist. Binary black hole mergers would be one of the strongest known sources of gravitational waves in the universe, and thus offer a good chance of directly detecting such waves.

As the orbiting black holes give off these waves, the orbit decays, and the orbital period decreases. This stage is called binary black hole inspiral. The black holes will merge once they are close enough. Once merged, the single hole settles down to a stable form, via a stage called ringdown, where any distortion in the shape is dissipated as more gravitational waves. In the final fraction of a second the black holes can reach extremely high velocity, and the gravitational wave amplitude reaches its peak.

Learn more about binary black hole here : brainly.com/question/16199119

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2 years ago
In an experiment, 1 mol of propane is burned to form carbon dioxide and water.
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3 years ago
At what time after being ejected is the boulder moving at a speed 20.7 m/s upward?
Svetlanka [38]

The time after being ejected is the boulder moving at a speed 20.7 m/s upward is 2.0204 s.

<h3>What is the time after being ejected is the boulder moving at a speed 20.7 m/s upward?</h3>

The motion of the boulder is a uniformly accelerated motion, with constant acceleration

a = g = -9.8 $$m / s^2

downward (acceleration due to gravity).

By using Suvat equation:

v = u + at

where: v is the velocity at time t

u = 40.0 m/s is the initial velocity

a = g = -9.8 $$m/s^2 is the acceleration

To find the time t at which the velocity is v = 20.7 m/s

Therefore,

$t=\frac{v-u}{a}=\frac{20.7-40}{-9.8}=2.0204 \mathrm{~s}

The time after being ejected is the boulder moving at a speed 20.7 m/s upward is 2.0204 s.

The complete question is:

A large boulder is ejected vertically upward from a volcano with an initial speed of 40.0 m/s. Ignore air resistance. At what time after being ejected is the boulder moving at 20.7 m/s upward?

To learn more about uniformly accelerated motion refer to:

brainly.com/question/14669575

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4 0
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