Two diverging light rays, originating from the same point, have an angle of 5° between them. After the rays reflect from a plane
mirror, what is the angle between them? Construct one possible ray diagram that supports your answer.
2 answers:
Answer:
5°
Explanation:
Two diverging light rays, originating from the same point, have an angle of 5° between them.
According to laws of reflection the angle of incidence is equal to the angle of reflection.
From the attached figure, it is clear that the after reflection from a plane mirror the angle between two rays will be 5°.
O be the originating point. m and n two diverging light rays. When they strikes at the plane mirror, the laws of reflection still fulfilled.
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Answer:
= 3,126 m / s
Explanation:
In a crash exercise the moment is conserved, for this a system formed by all the bodies before and after the crash is defined, so that the forces involved have been internalized.
the car has a mass of m = 1.50 kg a speed of v1 = 4.758 m / s and the mass of the train is M = 3.60 kg and its speed v2 = 2.45 m / s
Before the crash
p₀ = m v₁₀ + M v₂₀
After the inelastic shock
= m
+ M
p₀ =
m v₀ + M v₂₀ = m + M
We cleared the end of the train
M = m (v₁₀ - v1f) + M v₂₀
Let's calculate
3.60 v2f = 1.50 (2.15-4.75) + 3.60 2.45
= (-3.9 + 8.82) /3.60
= 1.36 m / s
As we can see, this speed is lower than the speed of the car, so the two bodies are joined
set speed must be
m v₁₀ + M v₂₀ = (m + M)
= (m v₁₀ + M v₂₀) / (m + M)
= (1.50 4.75 + 3.60 2.45) /(1.50 + 3.60)
= 3,126 m / s
Answer:
The archerfish must spit at a minimum speed of at an angle of
above the horizontal.
Explanation:
Hi
First of all, we need to find the angle above the horizontal at which the archerfish must spit, as we can see in the attachment this angle is .
Then we use the formula , as we clear it for
, we obtain,
, therefore the archerfish must spit at a minimum speed of
at an angle of
above the horizontal.
Answer:
The fringes are 4.7*10^-7 m apart, such that they are adjacent.
Explanation:
Using the formula for adjacent fringes given a single slit:
Δ
Δ
Δ
Hope this helps!