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Masteriza [31]
3 years ago
12

Electric Cars A 12 volt car battery has a capacity of 100 ampere-hours, supplying 2 A of current for 50 hours. How much ENERGY d

oes it store when fully charged? How does this compare to the contents of a 9 gallon petrol tank (1350 MJ) (express as percent)?
Physics
1 answer:
Elina [12.6K]3 years ago
6 0

Answer: a) 4.32 MJ ; b)  0.32%

Explanation: In order to solve this question we have to consider that power consume to full charge the battery is I*V

so we have 100 A-hours* 12 V = 1200 W*hours ( J*hour/s)

To convert to Joules

we have to multiply by 3600 ( seconds per hour) the Total energy stored in  the battery is:

E= 1200 J/s* 3600 s= 4.32 MJ

To compare with the energy of 9 gallon petrol tank  ( 1350 MJ)

%= E electric/ Epetrol= (4.32 MJ/(1350 MJ))*100%=0.32 %

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6 0
3 years ago
A parallel-plate capacitor is connected to a battery and becomes fully charged. The capacitor is then disconnected, and the sepa
AnnZ [28]

Answer:

Increases

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The expression for the capacitance is as follows as;

C=\frac{\epsilon _{0}A}{d}

Here, C is the capacitance, \epsilon _{0} is the permittivity of free space, A is the area and d is the distance between the parallel plate capacitor.

It can be concluded from the above expression, the capacitance is inversely proportional to the distance. According to the given problem, the capacitor is disconnected from the battery and the distance between the plates is increased. Then, the capacitance of the given capacitor will decrease in this case.

The expression for the energy stored in the parallel plate capacitor is as follows;

E=\frac{Q^{2}}{2C}

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Energy stored in the given capacitor is inversely proportional to the capacitor. The charge on the capacitor is constant. In the given problem, as the distance between the parallel plates is being separated, the energy stored in this capacitor increases.

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