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Bess [88]
3 years ago
12

A child is stationary on a swing.(a)The child is given a push by his brother to start him swinging.His brother applies a steady

force of 84 N over a distance of 0.25 m.(i) Calculate the work done by this force.(2)..............................................................................................................................................(ii) State how much energy is transferred by this force.(1)..............................................................................................................................................(iii) After several more pushes, the child has a kinetic energy of 71 J.The mass of the child is 27 kg.Show that the velocity of the child at this point is about 2.3 m/s.(2)(iv) Which one of these quantities changes in both size and direction while he is swinging?Put a cross ( ) in the box next to your answer.(1)Ahis gravitational potential energyBhis momentumCthe force of gravity acting on himDhis kinetic energy
Physics
1 answer:
lys-0071 [83]3 years ago
6 0

Answer:

Work done = Fs

Explanation:

(i) W = Fxs

= 84N x0.25m

= 21 Joules

(ii) Ek = 1/2mv^2

71 = 1/2×27×v^2

71×2/27 = v^2

v = 23m/s

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At temperatures near absolute zero, Bc approaches 0.142 T for vanadium, a type-I superconductor. The normal phase of vanadium ha
ioda

Answer:

b) field is zero,  c) the magnetic field does not change in intensity or direction

e) M = -H = Bo /μ₀ ,  g)  M = 0

Explanation:

Part b

superconductors are formed by so-called Coper pairs that are electrons linked through a distortion in the network, this creates that they must be treated as an entity so we have an even number of charge carriers and the material must behave with diamagnetic , Meissner effect, consequently the magnetic field inside its superconductor is zero

the correct answer is Zero

Part c

 outside the superconducting cylinder the magnetic field does not change in intensity or direction

Part E

Magnetization is defined by the equation

       B = μ₀ (H + M)

with field B it is zero inside the superconductors

        M = -H = Bo /μ₀

         

where Bo is the magnetic induction in the normal state

Part g

 As outside the cylinder there is no material zero magnetization

        M = 0

6 0
3 years ago
How much work is done when a hoist lifts a 210-kg rock to a height of 3 m? (Use 9.8 m/s2 for the acceleration due to gravity.)
Aleksandr [31]

Work done to lift the rock is 6174 Joule.

To find the answer, we need to know about the work done.

<h3>What's the work done?</h3>

Mathematically, work done = force × distance

<h3>What's the gravitational force acts on the stone here?</h3>

The gravitational force on the stone = mg

= 210× 9.8= 2058N

<h3>What's the work done to lift the stone?</h3>

Work done= 2058× 3

= 6174 Joule

Thus, we can conclude that the work done to lift the stone is 6174 Joule.

Learn more about the work done here:

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4 0
2 years ago
As an object falls to the ground its E, is converted to
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Kinetic Energy I’m not 100% shure tho
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3 years ago
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Westkost [7]

Answer:

640.5

Explanation: i got it right on acellus

5 0
3 years ago
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A marble rolls off a tabletop 1.15 m high and hits the floor at a point 4 m away from the tables edge in the
GREYUIT [131]

A marble rolls off a tabletop 1.15 m high and hits the floor at a point 4 m away from the edge of the table in the horizontal direction,

  • t= 0.45 seconds.
  • V=2.22m/s
  • VT=4.95 m/s

This is further explained below.

<h3>What is its speed when it hits the floor...?</h3>

Generally, the equation for motion is mathematically given as

S= ut + 0.5at²

Therefore

y = Voy t + 0.5gt^2

1 = 0.5x 98 x 6²

1=4.9t^2

t=\sqrt{0.2041 }

t= 0.45 seconds.

b) Horizontal motions are uniform.

V=Horizontal displacement/time

V=1/0.45

V=2.22m/s

C)

Vx: 2.22 m/s At bottom,

Vy² = Voy² + 2as

Vy² = 2x95x1

Vy² = 19.6

Total velocity

VT=\sqrt{( 2.22 m/)^2+19.6}

VT=4.95 m/s

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4 0
2 years ago
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