Answer:
b) field is zero, c) the magnetic field does not change in intensity or direction
e) M = -H = Bo /μ₀
, g) M = 0
Explanation:
Part b
superconductors are formed by so-called Coper pairs that are electrons linked through a distortion in the network, this creates that they must be treated as an entity so we have an even number of charge carriers and the material must behave with diamagnetic , Meissner effect, consequently the magnetic field inside its superconductor is zero
the correct answer is Zero
Part c
outside the superconducting cylinder the magnetic field does not change in intensity or direction
Part E
Magnetization is defined by the equation
B = μ₀ (H + M)
with field B it is zero inside the superconductors
M = -H = Bo /μ₀
where Bo is the magnetic induction in the normal state
Part g
As outside the cylinder there is no material zero magnetization
M = 0
Work done to lift the rock is 6174 Joule.
To find the answer, we need to know about the work done.
<h3>What's the work done?</h3>
Mathematically, work done = force × distance
<h3>What's the gravitational force acts on the stone here?</h3>
The gravitational force on the stone = mg
= 210× 9.8= 2058N
<h3>What's the work done to lift the stone?</h3>
Work done= 2058× 3
= 6174 Joule
Thus, we can conclude that the work done to lift the stone is 6174 Joule.
Learn more about the work done here:
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Kinetic Energy I’m not 100% shure tho
Answer:
640.5
Explanation: i got it right on acellus
A marble rolls off a tabletop 1.15 m high and hits the floor at a point 4 m away from the edge of the table in the horizontal direction,
- t= 0.45 seconds.
- V=2.22m/s
- VT=4.95 m/s
This is further explained below.
<h3>What is its speed when it hits the floor...?</h3>
Generally, the equation for motion is mathematically given as
S= ut + 0.5at²
Therefore
y = Voy t + 0.5gt^2
1 = 0.5x 98 x 6²
1=4.9t^2

t= 0.45 seconds.
b) Horizontal motions are uniform.
V=Horizontal displacement/time
V=1/0.45
V=2.22m/s
C)
Vx: 2.22 m/s At bottom,
Vy² = Voy² + 2as
Vy² = 2x95x1
Vy² = 19.6
Total velocity

VT=4.95 m/s
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