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erik [133]
3 years ago
9

how does the size of objects impact the pull of gravity between Earth and a baseball thrown into the air

Physics
2 answers:
Reil [10]3 years ago
3 0
it's how much it weighs and how much force is pushing on it like a egg if i drop it the weigh can cause it to break and how much force the gravity is pushing on it.
attashe74 [19]3 years ago
3 0
The size of an object tossed into the air doesn't matter. The gravitational force on it depends on its mass not its size. Gravity exerts more force on a small rock then on a large styrofoam wiffle ball.
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An apple has 6 J of energy. The apple sits on a counter 3 m high. What is the mass of the apple?
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Explanation:

PE= mgh

6 J= (3m) (9.81 m/s2) (mass)

mass=( 6)/(3×9.81)

mass= 0.20 Kg

7 0
3 years ago
Give two examples of common force fields and name the sources of these fields.
algol13
Electric force from electomagnetic force and force of gravity from gravitational force
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Is a fault or igneous intrusion that cuts across rock layers younger or older than the rocks it disrupts?
Ksju [112]
It is younger because there had to be rock layers already present for that to be possible.
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3 years ago
algunas fabricas de balones de futbol ubicadas en la costa inflan los balones que van a ser vendidos en ciudades como pasto,tunj
solmaris [256]

Answer:

Debido al cambio de volumen del gas dentro de la bola cuando se somete a una disminución de la presión y un aumento de la temperatura de la atmósfera.

Explanation:

La ubicación de las fábricas que fabrican las bolas que se encuentra en la costa como se indica en la pregunta es a baja altitud y una región más fría donde la presión atmosférica es más alta

Por lo tanto, la presión en la costa = p₁

La temperatura en la costa = T₁

El volumen de la pelota en la costa = V₁

Las condiciones en una ciudad con mayor altitud y temperatura tienen mayor presión atmosférica y temperatura de la siguiente manera;

La presión en la ciudad = p₂ <p₁

La temperatura en la ciudad = T₂> T₁

El volumen de la pelota en la costa = V₂

Por la ley de gas combinada de tenemos;

\dfrac{p_1 \times V_1}{T_1} = \dfrac{p_2 \times V_2}{T_2}

Allí el volumen de la pelota en la ciudad estará dado por la relación;

V_2 = V_1 \times \dfrac{p_1 }{P_2} \times  \dfrac{ T_2}{T_1 }

Dado que p₁> p₂ y T₂> T₁, entonces p₁/p₂> 1 y T₂/T₁> 1 y tenemos;

V₂ = V₁ × p₁/p₂ × T₂/T₁ = V₁ × X, donde X = p₁/p₂ × T₂/T₁> 1

V₂ = V₁ × X (> 1)

Por lo tanto, V₂> V₁ y el volumen ocupado por el gas aumenta cuando la pelota llega a la ciudad y la pelota está más firme.

7 0
3 years ago
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