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viva [34]
4 years ago
12

What is the name for B2(SO4)3

Chemistry
2 answers:
Nadya [2.5K]4 years ago
8 0

boron sulfate i think

UNO [17]4 years ago
7 0

It is Boron Sulfate

Hope this helps!

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What is the second most abundant isotope of oxygen
Talja [164]
Oxygen isotope<span> ratio cycles are cyclical variations in the ratio of the abundance of</span>oxygen<span> with an atomic mass of 18 to the abundance of </span>oxygen<span> with an atomic mass of 16 present in some substances, such as polar ice or calcite in ocean core samples, measured with the </span>isotope<span> fractionation.</span>
8 0
4 years ago
Which is the correct net ionic equation for the following reaction: 2 HBr (aq) + Co(OH)2 (aq) Imported Asset CoBr2 (aq) + 2 H2O
kow [346]

its B why because the reaction is good with B

6 0
3 years ago
How much ice (in grams) would have to melt to lower the temperature of 353 mL of water from 26 ∘C to 6 ∘C? (Assume the density o
Rashid [163]

Answer:

The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg

Explanation:

Heat gain by ice = Heat lost by water

Thus,  

Heat of fusion + m_{ice}\times C_{ice}\times (T_f-T_i)=-m_{water}\times C_{water}\times (T_f-T_i)

Where, negative sign signifies heat loss

Or,  

Heat of fusion + m_{ice}\times C_{ice}\times (T_f-T_i)=m_{water}\times C_{water}\times (T_i-T_f)

Heat of fusion = 334 J/g

Heat of fusion of ice with mass x = 334x J/g

For ice:

Mass = x g

Initial temperature = 0 °C

Final temperature = 6 °C

Specific heat of ice = 1.996 J/g°C

For water:

Volume = 353 mL

Density (\rho)=\frac{Mass(m)}{Volume(V)}

Density of water = 1.0 g/mL

So, mass of water = 353 g

Initial temperature = 26 °C

Final temperature = 6 °C

Specific heat of water = 4.186 J/g°C

So,  

334x+x\times 1.996\times (6-0)=353\times 4.186\times (26-6)

334x+x\times 11.976=29553.16

345.976x = 29553.16

x = 85.4197 kg

Thus,  

<u>The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg</u>

7 0
4 years ago
A mole of X reacts at a constant pressure of 43.0 atm via the reaction X(g)+4Y(g)→2Z(g), ΔH∘=−75.0 kJ Before the reaction, the v
hoa [83]

Answer:

The total energy change, ΔE, in kilojoules = -61.93 kJ

Explanation:

Relationship between ΔH, ΔE and work done is given by first law of thermodynamics.

ΔE = ΔH - PΔV

Where,

ΔH = Change in enthalpy

ΔE = Change in internal energy

PΔV = Work done

Given that,

ΔH = -75.0 kJ = -75000 J

P = 43.0 atm

ΔV = Final volume - initial volume

    = (2.00 - 5.00) = -3.00 L

PΔV = 43 × (-3.00) = -129 L atm

1 L atm = 101.325 J

-129 L atm = 129 × 101.325 = -13071 J

So ,

ΔE = ΔH - PΔV

     = (-75000 J) - ( -13071 J)

     =  -75000 J + 13071 J

     = -61929 J

Total energy change, ΔE = -61.929 kJ

3 0
4 years ago
Choose the example that is a protein:<br> •bread<br> •enzyme<br> •ORNA<br> •sugar
taurus [48]

Answer:

I think bread is the answer

4 0
4 years ago
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