All categories

4 years ago

What is the name for B2(SO4)3

Chemistry

2 answers:

Nadya [2.5K]4 years ago

8 0

boron sulfate i think

UNO [17]4 years ago

7 0

It is Boron Sulfate

Hope this helps!

You might be interested in

What is the second most abundant isotope of oxygen

Talja [164]

Oxygen isotope ratio cycles are cyclical variations in the ratio of the abundance ofoxygen with an atomic mass of 18 to the abundance of oxygen with an atomic mass of 16 present in some substances, such as polar ice or calcite in ocean core samples, measured with the isotope fractionation.

8 0

4 years ago

Which is the correct net ionic equation for the following reaction: 2 HBr (aq) + Co(OH)2 (aq) Imported Asset CoBr2 (aq) + 2 H2O

kow [346]

its B why because the reaction is good with B

6 0

3 years ago

How much ice (in grams) would have to melt to lower the temperature of 353 mL of water from 26 ∘C to 6 ∘C? (Assume the density o

Rashid [163]

Answer:

The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg

Explanation:

Heat gain by ice = Heat lost by water

Thus,

Heat of fusion + $m_{ice}\times C_{ice}\times (T_f-T_i)=-m_{water}\times C_{water}\times (T_f-T_i)$

Where, negative sign signifies heat loss

Or,

Heat of fusion + $m_{ice}\times C_{ice}\times (T_f-T_i)=m_{water}\times C_{water}\times (T_i-T_f)$

Heat of fusion = 334 J/g

Heat of fusion of ice with mass x = 334x J/g

For ice:

Mass = x g

Initial temperature = 0 °C

Final temperature = 6 °C

Specific heat of ice = 1.996 J/g°C

For water:

Volume = 353 mL

$Density (\rho)=\frac{Mass(m)}{Volume(V)}$

Density of water = 1.0 g/mL

So, mass of water = 353 g

Initial temperature = 26 °C

Final temperature = 6 °C

Specific heat of water = 4.186 J/g°C

So,

$334x+x\times 1.996\times (6-0)=353\times 4.186\times (26-6)$

$334x+x\times 11.976=29553.16$

345.976x = 29553.16

x = 85.4197 kg

Thus,

The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg

7 0

4 years ago

A mole of X reacts at a constant pressure of 43.0 atm via the reaction X(g)+4Y(g)→2Z(g), ΔH∘=−75.0 kJ Before the reaction, the v

hoa [83]

Answer:

The total energy change, ΔE, in kilojoules = -61.93 kJ

Explanation:

Relationship between ΔH, ΔE and work done is given by first law of thermodynamics.

ΔE = ΔH - PΔV

Where,

ΔH = Change in enthalpy

ΔE = Change in internal energy

PΔV = Work done

Given that,

ΔH = -75.0 kJ = -75000 J

P = 43.0 atm

ΔV = Final volume - initial volume

= (2.00 - 5.00) = -3.00 L

PΔV = 43 × (-3.00) = -129 L atm

1 L atm = 101.325 J

-129 L atm = 129 × 101.325 = -13071 J

So ,

ΔE = ΔH - PΔV

= (-75000 J) - ( -13071 J)

= -75000 J + 13071 J

= -61929 J

Total energy change, ΔE = -61.929 kJ

3 0

4 years ago

Choose the example that is a protein: •bread •enzyme •ORNA •sugar

taurus [48]

Answer:

I think bread is the answer

4 0

4 years ago