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SSSSS [86.1K]
2 years ago
5

If a dog has a mass of 16.1 kg, what is its mass in the following units? Use scientific notation in all of your answers.

Chemistry
1 answer:
nekit [7.7K]2 years ago
3 0

Answer:

16.1\times 10^3\ \text{g}

16.1\times 10^{6}\ \text{mg}

16.1\times 10^{9}\ \mu\text{g}

Explanation:

Mass of dog = 16.1\ \text{kg}

1\ \text{kg}=10^{3}\ \text{g}

1\ \text{kg}=10^{6}\ \text{mg}

1\ \text{kg}=10^{9}\ \mu\text{g}

So,

16.1\ \text{kg}=16.1\times 10^3\ \text{g}

16.1\ \text{kg}=16.1\times 10^{6}\ \text{mg}

16.1\ \text{kg}=16.1\times 10^{9}\ \mu\text{g}

Mass of the dog in the other units is 16.1\times 10^3\ \text{g}, 16.1\times 10^{6}\ \text{mg} and 16.1\times 10^{9}\ \mu\text{g}.

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Question 25———-A, YA are two isotopes of element A.
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Answer:

Option C. 1

Explanation:

Step 1:

Determination of the Neutron of both isotopes. This is illustrated below.

For isotope y xA:

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Neutron = y – x

For isotope (y + 1) xA:

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Neutron = y + 1 – x

Step 2:

Determination of the difference between the neutron number of both isotopes. This is illustrated below:

For isotope y xA:

Neutron number = y – x

For isotope (y + 1) xA:

Neutron number = y + 1 – x

Difference in neutron number

=> (y + 1 – x) – (y – x)

=> y + 1 – x – y + x

Rearrange

=> y – y + 1 – x + x

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Answer : The value of work done for the system is 1144.69 J

Explanation :

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Now we have to calculate the moles of nitrogen gas.

The balanced chemical reaction is,

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From the balanced reaction we conclude that

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Now we have to calculate the volume of nitrogen gas.

Using ideal gas equation:

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where,

P = Pressure of N_2 gas = 1.00 atm

V = Volume of N_2 gas = ?

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T = Temperature of N_2 gas = 22^oC=273+22=295K

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Expansion work = 1.00 atm × 11.3 L

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Expansion work = 11.3 × 101.3 = 1144.69 J

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