Answer:
On edge nuity, it is 79.
Explanation:
Please read the explanation.
Since u have no coefficients, this problem is super easy.
You just add your products, 115.5+69.91 = 185.41
Then add your reactants: 49.8+56.5= 106.3
Then subtract your reactants from your product and round to the nearest whole number.
106.3-185.41=79
It's really easy. Once u understand it, you can do any problem like this. If there is coefficients, just multiply the coefficient by the amount given to you in the problem.
Two moles of SO2 means 1.204x10^24 molecules, since there are 3 atoms in one molecule, multiply 1.204 x10^24 by 3 and you get 3.612x10^24.
The chemical formula for the compound containing 8.6 mol of sulfur and 3.42 mol of phosphorus is P₂S₅
<h3>How do I determine the formula of the compound?</h3>
From the question given above, the following data were obatined:
- Sulphur (S) = 8.6 moles
- Phosphorus (P) = 3.42 mole
- Chemical formula =?
The chemical formula of the compound can be obtained as follow:
Divide by their molar mass
S = 8.6 / 32 = 0.26875
P = 3.42 / 31 = 0.11032
Divide by the smallest
S = 0.26875 / 0.11032 = 2.44
P = 0.11032 / 0.11032 = 1
Multiply by 2 to express in whole number
S = 2.44 × 2 = 5
P = 1 × 2 = 2
Thus, the chemical formula is P₂S₅
Learn more about empirical formula:
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Supposing a temperature of 25 degrees and supposing that all
activity coefficients are 1
pH = -log[H+]
pOH = -log[OH-]
pH + pOH = 14
Thus a pH of 2.50 would mean that the [H+], the concentration of the hydrogen
ion, would be 10^(-2.50)
pH + pOH = 14
pOH = 14 - pH = 14 - 2.5 = 11.5
MOH- levels would be coordinated with pOH
pOH = -log[OH-] ==> [OH-] = [MOH-] = 10^-pOH = 10^-11.5 = 3.2 x 10^-12
Therefore, MOH¯ = 3.2 × 10¯12 M
Based off the salt levels in each water.
