B. motion, because if a body isn’t moving and you apply a moving force to it it will then cause the body to be put into motion as well
They got back in the Lunar Explorer Module
A. Decreasing negatively, velocity is constant
B. Object at rest, velocity is zero
C. Decreasing negatively, velocity is constant
D. Increasing positively, velocity is constant
Answer:
Part a)
Weight on surface of other planet = 213.4 N
Part b)
Mass of the Astronaut = 66.0 kg
Part c)
Weight of the Astronaut on Earth = 646.8 N
Explanation:
Part A)
Weight of the Astronaut on the surface of the planet is given as
here we will have
also we have
now we have
Part B)
Mass of the Astronaut will always remains the same
So it will be same at all positions and all planets
So its mass will be
m = 66.0 kg
Part C)
Weight of the Astronaut on Earth is given as
Answer:
Explanation:
To find the angular velocity of the tank at which the bottom of the tank is exposed
From the information given:
At rest, the initial volume of the tank is:
where;
height h which is the height for the free surface in a rotating tank is expressed as:
at the bottom surface of the tank;
r = 0, h = 0
∴
0 = 0 + C
C = 0
Thus; the free surface height in a rotating tank is:
Now; the volume of the water when the tank is rotating is:
dV = 2π × r × h × dr
Taking the integral on both sides;
replacing the value of h in equation (2); we have:
Since the volume of the water when it is at rest and when the angular speed rotates at an angular speed is equal.
Then
Replacing equation (1) and (3)
Finally, the angular velocity of the tank at which the bottom of the tank is exposed = 10.48 rad/s