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Mariana [72]
3 years ago
8

Let me know if you need help figuring out how to make something in little alchemy 2.

Physics
2 answers:
Y_Kistochka [10]3 years ago
7 0

Answer:

ok

Explanation:

Kaylis [27]3 years ago
3 0

Answer:ok

Explanation:

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The triceps muscle in the back of the upper arm extends the forearm. This muscle in a professional boxer exerts a force of 2615
mart [117]

Answer:

0.68 kg-m²

Explanation:

F = Force applied by the muscle = 2615 N

r = effective perpendicular lever arm = 2.85 cm = 0.0285 m

α = Angular acceleration of the forearm = 110.0 rad/s²

I  = moment of inertia of the boxer's forearm = ?

Torque is given as

τ = I α                                   eq-1

Torque is also given as

τ = r F                                   eq-2

using eq-1 and eq-2

r F =  I α

(0.0285)(2615) = (110.0) I

I = 0.68 kg-m²

7 0
3 years ago
if a metal object was cut on half how much heat will be required to raise both half to a specific temperature
il63 [147K]

suppose the mass of a metal object be m and its specific heat capacity be s, and, H joules of heat is required to raise its temperature by t degrees Celsius

Than H is given by relation, H = mst

Now if this object is cut in two half's, than mass of half part will also be half <em>i.e. </em>M/2

So heat required to heat the half part will be = (\frac{m}{2}) st =\frac{mst}{2} = H/2  

Hence, the heat required to raise the half object to a specific temperature will also become half.

3 0
3 years ago
Imagine a player throwing a football. Explain the action of what is happening to the hand and ball, as well as describe the acti
garri49 [273]

Answer:

Explanation:

When a player throws a football , he applies force on the ball , due to which ball accelerates in forward direction . This is the action force .

The ball also applies a force on the hand of the player . Due to it the player experiences a pushing force in backward direction . This is reaction force .

Due to this force , the player does not move in backward direction because of frictional force of the ground . The frictional force keeps him stationary .

7 0
3 years ago
Use Newton's laws to explain why a falling object dropped from a 57m tower accelerates initially but then reaches constant veloc
snow_lady [41]

Answer:

At the point of dropping the object, by Newton's first law due to gravitational force F_g = m × g, accelerates

By Newton's Second law the object reaches impacts on the air with the gravitational force resulting in changing momentum of m×(Final Velocity - Initial Velocity)

As the velocity increases, the rate of change of momentum becomes equivalent to the gravitational force and by Newton's third law, the action action and reaction are equal and opposite hence they cancel each other out

The body then moves at a constant uniform motion down according to Newton's first law

Explanation:

At the point the object of mass, m, is dropped from the height of the tower, the only force acting on the object is the gravitational force such that the object has an acceleration which is the acceleration due to gravity, g, and the gravitational force is therefore = m × g

As the speed of the object increases while the object is falling with the gravitational acceleration the rate at which the object cuts through layers of air which (by Newton's first law of motion, are at rest ) has some buoyancy effect also increases therefore, the object is constantly increasingly changing the momentum of the air which by Newton's second law results, at an high enough velocity, and by Newton's third law, in a force equal to the applied gravitational force

Therefore, the force of the air drag becomes equal to the gravitational force, cancelling each other out and the object then moves according to Newton;s first law, in uniform motion of a constant speed while still falling down.

5 0
3 years ago
An object travels 20 m in 10s What is its speed?
ella [17]

speed=distance/time

distance=20m

time=10s

speed=?

speed=20×10

speed=200m/s

3 0
3 years ago
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