Answer:
See attached picture.
Explanation:
Hello,
In this case, accounting for the IUPAC rules for the nomenclature of ketones, for the given name the structure is shown on the attached picture wherein the methyl is seen at the fourth carbon and the carbonyl at the second one in the 7-carbon chain.
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Answer:
![V_{HI}=236LHI](https://tex.z-dn.net/?f=V_%7BHI%7D%3D236LHI)
Explanation:
Hello,
In this case, for the given balanced chemical reaction:
![H_2(g)+I_2(g)\rightarrow 2HI(g)](https://tex.z-dn.net/?f=H_2%28g%29%2BI_2%28g%29%5Crightarrow%202HI%28g%29)
Thus, since hydrogen and hydrogen iodide are in a 1:2 mole ratio, we can easily compute the yielded volume as shown below:
![V_{HI}=118LH_2*\frac{2molHI}{1molH_2} \\\\V_{HI}=236LHI](https://tex.z-dn.net/?f=V_%7BHI%7D%3D118LH_2%2A%5Cfrac%7B2molHI%7D%7B1molH_2%7D%20%5C%5C%5C%5CV_%7BHI%7D%3D236LHI)
Thus, is possible, due to the Avogadro's law which allows to relate moles and volume by a directly proportional relationship.
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When there isn't enough oxygen for Oxidative Phosphorylation to occur, anaerobic respiration occurs. You can't produce ATP across the inner of the mitochondrial membrane or in the Krebs cycle if you don't have Oxidative Phosphorylation. As a result, the yeast employs anaerobic respiration to keep Glycolysis running, resulting in 4 ATP molecules (Net: 2) each Glucose molecule that is converted to Pyruvate.
Allowing NADH to lose hydrogen allows it to be converted to NAD, which can then be utilized to oxidize glucose to pyruvate, which produces ATP, and so on. This is best illustrated in a diagram, in my opinion.
Answer:
a. Ethanol.
b. 4.21 mL H2O.
c. 87.8%
Explanation:
Hello,
- For the limiting reactant, the available amount of ethanol is less than the ideal amount of ethanol that would react with the given amount of oxygen, that's why it is the limiting one.
- You will find the calculations in the attached picture; take into account that the molecular mass of water is 18 g/mol and ethanol 46 g/mol.
- The percent yield is allowed to be computed in terms of volume as well, because the relationships are conserved.
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