A solution of rubbing alcohol is 75.7 % (v/v) isopropanol in water. How many milliliters of isopropanol are in a 87.7 mL sample
1 answer:
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1066.7 ml of the stock solution must start with, preparing 2.00 L of a 0.800 M NaNO3 solution.
<h3>What is volume?</h3>Volume is the space occupied by a three-dimensional object.
By the formula
M1 is the initial molarity, 1.5 M
M2 is the final molarity, 0.800 M
V1 is the initial volume
V2 is the final volume, 2.00 L
Putting the values in the equation
Thus, the initial volume is 1066.7 ml
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