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Charra [1.4K]
3 years ago
13

Without simplifying, select all the expressions that represent a rational number. Group of answer choices LaTeX: 4\frac{2}{3}+\f

rac{\sqrt{3}}{9} 4 2 3 + 3 9 4 2 3 + 3 9 4 2 3 + 3 9 LaTeX: 4\frac{2}{3}\times\frac{8}{\sqrt{3}} 4 2 3 × 8 3 4 2 3 × 8 3 4 2 3 × 8 3 LaTeX: 4\frac{2}{3}-\frac{\sqrt{4}}{8} 4 2 3 − 4 8 4 2 3 − 4 8 4 2 3 − 4 8 LaTeX: 4\frac{2}{3}\times\frac{\sqrt{3}}{9} 4 2 3 × 3 9 4 2 3 × 3 9 4 2 3 × 3 9 LaTeX: 4\frac{2}{3}\div\frac{\sqrt{4}}{8}
Mathematics
1 answer:
Inessa05 [86]3 years ago
3 0

Answer:

Option C.

Step-by-step explanation:

We know the following properties,

1. Product of an irrational number and a non-zero rational number is always an irrational number.

2. Sum of a rational and an irrational number is always an irrational number.

3. Sum or products of rational numbers are always a rational number.

In option A,

4\frac{2}{3}+\frac{\sqrt{3}}{9}

Here, \sqrt{3} is an irrational number.

\frac{\sqrt{3}}{9} is an irrational number using property 1.

4\frac{2}{3}+\frac{\sqrt{3}}{9} is an irrational number using property 2.

So, using the above properties we can say that this expression represents an irrational number.

Similarly,

In option B,

4\frac{2}{3}\times\frac{8}{\sqrt{3}}

Here, \sqrt{3} is an irrational number. So, using the above properties we can say that this expression represents an irrational number.

In option C,

4\frac{2}{3}-\frac{\sqrt{4}}{8}

Here, \sqrt{4}=2, which is a rational number.

So, this expression represents a rational number using property 3.

In option D,

4\frac{2}{3}\times\frac{\sqrt{3}}{9}

Here, \sqrt{3} is an irrational number. So, using the above properties we can say that this expression represents an irrational number.

Therefore, the correct option is C.

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