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2 years ago

A compound and oxidant react to produce heat and a new product is what reaction

Chemistry

1 answer:

Karolina [17]2 years ago

4 0

Answer:

A compound and oxidant react to produce heat and new product is chemical reaction.

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What is the oxidation number of Cl in chlorate ion ClO3?

Kryger [21]

The correct answer to this question is "5." the oxidation number of cl in ClO3 will be a positive 5 because oxygen is naturally a -2 charge. times that by three and then account for the negative charge of the CLO3- ion.

8 0

3 years ago

Read 2 more answers

The solubility of nitrogen gas at 25 ◦C and 1 atm is 6.8×10−4 mol/L. If the partial pressure of nitrogen gas in air is 0.76 atm,

iris [78.8K]

Answer:

Concentration of dissolved nitrogen = 5.2 × 10⁻⁴ mol/L

Explanation:

More the pressure of the gas, more will be its solubility.

So, for two different pressure, the relation between them is shown below as:-

$\frac {P_1}{C_1}=\frac {P_2}{C_2}$

Given ,

P₁ = 1 atm

P₂ = 0.76 atm

C₁ = 6.8 × 10⁻⁴ mol/L

C₂ = ?

Using above equation as:

$\frac{1\ atm}{6.8\times 10^{-4}\ mol/L}=\frac{0.76\ atm}{C_2}$

$C_2=\frac{0.76\times 6.8\times 10^{-4}}{1}\ mol/L$

<u>Concentration of dissolved nitrogen = 5.2 × 10⁻⁴ mol/L</u>

5 0

2 years ago

In 1890 there were more gray-winged moths than white-winged moths due to?

lys-0071 [83]

Answer:

thank u

Explanation:

7 0

3 years ago

Read 2 more answers

what is the concentration of a NaCl solution, in Molarity, if you add 59.76 g of NaCl into 270 mL of H2O

enot [183]

Hey there!

Molar mass NaCl = 58.44 g/mol

Number of moles

n = mass of solute / molar mass

n = 59.76 / 58.44

n = 1.0225 moles of NaCl

Volume in liters:

270 mL / 1000 => 0.27 L

Therefore:

M = number of moles / volume ( L )

M = 1.0225 / 0.27

= 3.78 M

Hope that helps!

7 0

3 years ago

When an aqueous solution of silver nitrate is

Andre45 [30]

Answer:

$K^{+}$ and $NO_{3}^{-}$

Explanation:

The equation for the reaction is AgNO3(aq) + KCl(aq) ==> AgCl(s) + KNO3(aq)

With all the ions, it is

$Ag^{+}$ (aq) + $NO_{3} ^{-}$ (aq) + $K^{+}$ (aq) + $Cl^{-}$ (aq) ==> AgCl(s) +

$K^{+}$ and $NO_{3} ^{-}$ do not change, so they are the spectator ions and are removed

The ionic equation is:

$Ag^{+}$ (aq) + $Cl^{-}$ (aq) ==> AgCl(s)

8 0

2 years ago