Answer:
5 cm³.
Explanation:
From the question given above, the following data were obtained:
Volume of water = 35 mL
Volume of water + Rock = 40 mL
Volume of Rock =.?
The volume of the rock can be obtained as follow:
Volume of Rock = (Volume of water + Rock) – (Volume of water)
Volume of Rock = 40 – 35
Volume of Rock = 5 mL.
Finally, we shall convert 5 mL to cm³.
This can be obtained as follow:
1 mL = 1 cm³
Therefore,
5 mL = 5 mL × 1 cm³ / 1 mL
5 mL = 5 cm³
Thus, we can say that the volume of the rock is 5 cm³.
Answer:
Mass = 101891.2 g
Explanation:
Given data:
Mass of ammonia needed = ?
Mass of ammonium sulfate produced = 396 Kg = 396 ×1000 = 396000 g
Solution:
Chemical equation:
2NH₃ + H₂SO₄ → (NH₄)₂SO₄
Number of moles of (NH₄)₂SO₄:
Number of moles = mass/molar mass
Number of moles = 396000 g / 132.14 g/mol
Number of moles = 2996.8 mol
Now we will compare the moles of ammonia and ammonium sulfate
(NH₄)₂SO₄ : NH₃
1 : 2
2996.8 : 2/1×2996.8 = 5993.6 mol
Mass of ammonia needed:
Mass = number of moles × molar mass
Mass = 5993.6 mol × 17 g/mol
Mass = 101891.2 g
<u>Given:</u>
Rate of appearance of O2 = 0.250 M/s
Time period = 5.50 s
<u>To determine:</u>
The concentration of O2 formed
<u>Explanation:</u>
2O3 (g) ↔ 3O2 (g)
Rate of appearance of O2 = 1/3 * Δ[O2]/Δt
Based on the given data:
0.250 M/s = 1/3 * [O2]/5.50 s
[O2 ] = 0.250 Ms⁻¹ * 3 * 5.50 s = 4.125 M
Ans: Amount of oxygen formed is 4.13 M
Answer:
The volume of the liquid should be measured before it is heated.
Explanation:
Answer:
i)a. P & R
b. Q& S
ii) R
iii) Atomic no & Atomic radius
2)a. C4H10
b. CH3Cl
