Answer:
D. The electron moved up to an energy level and has an energy of 21.72 x 10−19 J.
The density of mercury is <span>5.43 g/cm³.</span>
1) All the CO2 comes from the C24 H30 N3 O
2) To balance C from CO2 with C from C24, the ratio of cC24 H30 N3 O to CO2 is 24 / 1
3) Convert 1.20 g of CO2 to number of moles
number of moles = mass in grams / molar mass
mass = 1.20 g
molar mass = 12.01 g/mol + 32.00 g/mol = 44.01 g/mol
number of moles = 1.2 g / 44.01 g/mol = 0.0273 mol
4) proportion
1 mol C24 H30 N3 O / 24 mol CO2 = x / 0.0273 mol CO2
=> x = 0.0273 mol CO2 * 1 mol C24H30N3O / 24 mol CO2 = 0.00114 mol C24H30N3O
5) Convert 0.00114 mol C24H30N3O to grams
molar mass = 376.5 g/mol
mass = 0.00114 mol * 376.5 g/mol = 0.429 g
6) mass percent in the mixture
mass percent = (mass of lsd / mass of mixture) * 100 = (0.429g / 1.0g) * 100 = 42.9%
Answer: 42.9%
Answer:
Mass of KOH = 497.78 g
Explanation:
Given data
mass of KOH = ?
number of KOH molecules = 5.34 × 10²⁴
molar mass of KOH = 56.12 g/mol
Solution
1st we find out the number of moles of KOH
<em>number of moles = number of molecules given / Avogadro number
</em>
number of moles of KOH = 5.34 × 10²⁴ / 6.022 × 10²³
number of moles of KOH = 8.87 mol
Now we find out the mass of KOH
<em>Mass of KOH = moles × molar mass</em>
Mass of KOH = 8.87 mol × 56.12 g/mol
Mass of KOH = 497.78 g
Explanation:
Please provide the chemical reaction to allow others to help solve this problem. Assuming the system is in STP, then use the molar volume to solve for the moles of Oxygen and then use the mole ratio to determine the moles of NO2 that is produced as a result of this reactant
