Calculate the pressure in atmospheres of 0.5 mol of Helium ( He) at 20°C & occupying 2.50 L.
1 answer:
Answer:
4.811 atm.
Explanation:
- We can use the general law of ideal gas:<em> PV = nRT.</em>
where, P is the pressure of the gas in atm (P = ?? atm).
V is the volume of the gas in L (V = 2.5 L).
n is the no. of moles of the gas in mol (n = 0.5 mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K),
T is the temperature of the gas in K (T = 20°C + 273 = 293 K).
<em>∴ P = nRT/V =</em> (0.5 mol)(0.0821 L.atm/mol.K)(293 K)/(2.5 L) = <em>4.811 atm.</em>
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