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3 years ago

I know what the answer is to part A but not part B

Physics

2 answers:

Olin [163]3 years ago

7 0

Answer:

plz show the questions clearly

cupoosta [38]3 years ago

5 0

You need to write the question

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Two spherical point charges each carrying a charge of 40 μC are attached to the two ends of a spring of length 20 cm. If its spr

PolarNik [594]

Answer:

$x=3$

Explanation:

From the question we are told that:

Charge $Q=40 \mu C$

Length $L=20cm=0.20m$

Spring constant $k=120Nm^{-1}$

Generally the equation for Force between Charges is mathematically given by

$F=k\frac{q_1 q_2}{r^2}$

$F=9*10^9\frac{40*10^{-6}^2}{0.2^2^2}$

$F=360N$

Therefore

$F=kx$

$x=\frac{F}{k}$

$x=\frac{360}{120}$

$x=3$

5 0

3 years ago

What happens if you jump on a shock absorbent mattress?

kkurt [141]

A shock absorbent mattress is built such that the boxspring of the bed absorbs pressure that is exerted to the bed. Hence, if you jump on the mattress, you would not bounce up and down as much as a normal mattress because the springs do not oscillate much. This is done to endure wear and tear.

7 0

3 years ago

Two gliders on an air track collide in a perfectly elastic collision. Glider A has a mass of 1.1 kg and is initially travelling

Eva8 [605]

m1= mass 1 = 1.1 kg

Vi1 = initial velocity 1 = 2.7 m/s

m2= 2.4 kg

V2i = -1.9 m/s

We assume east as positive and west as negative.

Apply the formulas:

Vf1 = ?

$vf1=(\frac{m1-m2}{m1+m2})Vi1+(\frac{2m2}{m1+m2})Vi2$

Replacing:

$Vf1=\frac{(1.1-2.4)}{(1.1+2.4)}2.7+\frac{(2\times2.4)}{(1.1+2.4)}-1.9$ $Vf1=(\frac{-1.3}{3.5})2.7+(\frac{4.8}{3.5})-1.9$ $Vf1=-1-2.6=-3.6\text{ m/s}$

Answer: 3.6 m/s west

6 0

1 year ago

Two identical conducting spheres A and B carry equal charge. They are separated by a distance much larger than their diameters.

VashaNatasha [74]

What a delightful little problem !
Here's how I see it:

When 'C' is touched to 'A', charge flows to 'C' until the two of them are equally charged. So now, 'A' has half of its original charge, and 'C' has the other half.

Then, when 'C' is touched to 'B', charge flows to it until the two of them are equally charged. How much is that ? Well, just before they touch, 'C' has half of an original charge, and 'B' has a full one, so 1/4 of an original charge flows from 'B' to 'C', and then each of them has 3/4 of an original charge.

To review what we have now: 'A' has 1/2 of its original charge, and 'B' has 3/4 of it.

The force between any two charges is:

F = (a constant) x (one charge) x (the other one) / (the distance between them)².

For 'A' and 'B', the distance doesn't change, so we can leave that out of our formula.

The original force between them was 3 = (some constant) x (1 charge) x (1 charge).

The new force between them is F = (the same constant) x (1/2) x (3/4) .

Divide the first equation by the second one, and you have a proportion:

3 / F = 1 / ( 1/2 x 3/4 )

Cross-multiply this proportion:

3 (1/2 x 3/4) = F

F = 3/2 x 3/4 = 9/8 = 1.125 newton.

That's my story, and I'm sticking to it.

5 0

3 years ago

A piston is filled with gas. When the pressure is increasing, what is happening to the volume? Assume that all other properties

Kryger [21]

The correct answer is letter C. Volume is decreasing. For a fixed amount of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional.

3 0

3 years ago