Answer:
Explanation:
The food chopping appliances in this scenario should adapt use of digital image processing systems to capture the images after the chopping begins. Certain variables can be defined like food particles size, area etc. This will help deciding a threshold for the variable and then the comparator used in the system will(run by real time operating system) compare the threshold size with the digital image size of particles. If the size is found small then the speed of motor should reduce meaning we have chopped the food as per our need. In case the chopping is not done aptly, the same can be enhanced by increasing the speed of motor till the final outcome is reached
A geyser is actually a devise that coverts electrical energy
into heat energy for heating up water. The heating element that is inside the
geyser actually gets heated up and then in turn it heats the water in contact
with it within the geyser. There is also a thermostat device within the geyser
that cuts off the heating when the water temperature reaches the desired level.
This helps in stopping of electrical energy loss. One inlet brings in cold
water while another outlet gets rid of the hot water. When the temperature of
the water falls below the desired level the heating is again started by the
thermostat.
<span>The answer would be convection currents. Convection happens when atoms with a lot of heat energy in a liquid or gas transfer and get the room of particles with fewer heat energy. Heat energy is transported from hot places to cooler places by convection.</span>
Answer:
option (b) 4900 N
Explanation:
m = 2000 kg, R = 6380 km = 6380 x 10^3 m, Me = 5.98 x 10^24 kg, h = R
F = G Me x m / (R + h)^2
F = G Me x m / 2R^2
F = 6.67 x 10^-11 x 5.98 x 10^24 x 2000 / (2 x 6380 x 10^3)^2
F = 4900 N
Solution:
Let the slope of the best fit line be represented by '
'
and the slope of the worst fit line be represented by '
'
Given that:
= 1.35 m/s
= 1.29 m/s
Then the uncertainity in the slope of the line is given by the formula:
(1)
Substituting values in eqn (1), we get
= 0.03 m/s
