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GREYUIT [131]
4 years ago
10

The formula to find the period of orbit of a satellite around a planet is T2=(4π2GM)r^3 where r is the orbit’s mean radius, M is

the mass of the planet, and G is the universal gravitational constant. If you are given all the values except r, how do you rewrite the formula to solve for r?

Mathematics
2 answers:
Illusion [34]4 years ago
7 0

have a nice day! I got it correct on Plato!

andriy [413]4 years ago
5 0
<span>The formula to find the period of orbit of a satellite around a planet is T^2=(4π^2/GM)r^3 where r is the orbit’s mean radius, M is the mass of the planet, and G is the universal gravitational constant. To find the value of r, we rewrite r^3 = (T^2GM/4π^2) or r = (T^2GM/4π^2)^(1/3)</span>
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Please Help I'm Confused.
Tatiana [17]
It examines the knowledge of the basic calculation. According to the topic, parallelogram ABCD & AB//CD
so AB=CD
Since MAB=-5 so MCD = MAB=-5 then the answer might be “-5”
6 0
2 years ago
What should you substitute for y in the bottom equation to solve the system by the substitution method?
Contact [7]
Answer: y= -x-5


Step 1: Determine which equation to change

Since we will be using the substitution method, we will need to substitute y from the bottom equation with information from the top equation. This will be the equation we change.

Step 2: Change the equation

Let’s rewrite the equation we will be working with.

3x+3y= -15

Our goal will be to get y alone on the left side. To start, let’s subtract 3x from both sides, leaving only 3y on the left side.

3x+3y= -15
3y= -3x-15

Now we need to get y completely alone by eliminating the coefficient of 3. Let’s do this by dividing each term by 3.

3y= -3x-15
y= -x-5


This is your answer. Hope this helps! Comment below for more questions.
3 0
3 years ago
Solve the linear system using substitution
levacccp [35]
Hello there!

3x - y = 3
-x + y = 3

We need to solve 3x - y = 3 for y

Let start by adding -3x to both sides

3x - y = 3

3x - 3x - y = 3 - 3x

-y = 3 - 3x
We cannot leave the variable with a negative sign. We must multiply both sides by -1

-y * -1= (3 - 3x)-1

y = 3x - 3

Substitute 3x -3 for y in -x+y=3

-x + y = 3

-x + 3x - 3 = 3

2x - 3 = 3

2x = 3 + 3

2x = 6

x = 6/2

x = 3

Now substitute 3 for x in y=3x -3

y = 3x - 3

y = 3(3) - 3

y= 9 - 3

y= 6

Thus,

The answer is x=3 and y=6

It is always my pleasure to help students like you :)

As always, I am here to help!


7 0
4 years ago
Lim (x^3-8)/(x)<br>x-2 ​
leonid [27]
Here you go!!! Hope this helps

3 0
3 years ago
Where to locate the nonnegative abscissa, positive ordinate
Fofino [41]
The location to the nonegative abscissa, positive ordinate is in the Q1 it means it is in the fisrt quadrant as seen in the next image: http://www.mathnstuff.com/math/spoken/here/1words/q/q2.htm
Hope this helps
4 0
3 years ago
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