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GREYUIT [131]
4 years ago
10

The formula to find the period of orbit of a satellite around a planet is T2=(4π2GM)r^3 where r is the orbit’s mean radius, M is

the mass of the planet, and G is the universal gravitational constant. If you are given all the values except r, how do you rewrite the formula to solve for r?

Mathematics
2 answers:
Illusion [34]4 years ago
7 0

have a nice day! I got it correct on Plato!

andriy [413]4 years ago
5 0
<span>The formula to find the period of orbit of a satellite around a planet is T^2=(4π^2/GM)r^3 where r is the orbit’s mean radius, M is the mass of the planet, and G is the universal gravitational constant. To find the value of r, we rewrite r^3 = (T^2GM/4π^2) or r = (T^2GM/4π^2)^(1/3)</span>
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Hey guys please help me and try to show ur work
Mamont248 [21]
This is the net of a rectangular prism, so the surface area can be found with the formula: SA=2lw+2wh+2lh

In this case,

l=10.5
w=6.4
h=4

Now, we can plug these numbers into the equation:

SA= (2)(10.5)(6.4) + (2)(6.4)(4) + (2)(10.5)(4)
SA= 134.4 + 51.2 + 84
SA = 269.6 cm

Therefore, the answer is D.
6 0
3 years ago
There are 30 treasures hidden in a castle in a video game. Latoya found 80% of them. How many of the treasures did Latoya find?
inn [45]

Answer:

It is 24

Step-by-step explanation:

trust me

3 0
3 years ago
Read 2 more answers
16/25 divided by 15/8​
MA_775_DIABLO [31]

Answer:

i think it's 20/8

Step-by-step explanation:

7 0
3 years ago
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If the areas of two similar hexagons are to each other as 5 : 2, and one side of the first hexagon is 25, what is the correspond
Inessa05 [86]
5:2 = 25:x

25 = 5 * 5
so
x = 2 * 5 = 10


its D
3 0
3 years ago
Find any relative extrema of the function. (Round your answers to three decimal places.)
Strike441 [17]

(x) = arcsec(x) − 8x

f'(x) = d/dx( arcsec(x) − 8x )

<span> 1/xsqrt( x^2 - 1) - 8</span>

f'(x) = 0

1/xsqrt( x^2 - 1) - 8 = 0

8 x sqrt (x^2-1) = 1

<span> ( 8 x sqrt (x^2-1) )^2 = 1</span>

64 x^2 ( x^2 - 1) = 1

64 x^4 - 64 x^2 =1

64 x^4 - 64 x^2 - 1 = 0

x = 1.00766 , - 1.00766

<span> x =   - 1.00766</span>

f(- 1.00766) = arcsec(- 1.00766) − 8( - 1.00766)

f( - 1.00766 ) = 11.07949

x = 1.00766

f(1.00766) = arcsec(1.00766) − 8( 1.00766)

f(1.00766 ) = -7.93790

relative maximum (x, y) = (- 1.00766 , 11.07949 ) relative minimum (x, y) = ( 1.00766 , -7.93790  )


8 0
4 years ago
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