Answer:
n and (n - 1) are consecutive integers.
Step-by-step explanation:
We are given 'n', a positive integer.
This 'n' can either be odd or even.
Case I:
When 'n' is odd
The n - 1 is even.
Note that the product of odd and even is always even. That is the product of n and (n - 1) is even.
Case II:
when 'n' is even
Then n - 1 is odd.
Again, using the similar logic we can say that the product of n and n - 1 should be even because here, 'n - 1' is even and 'n' is odd.
Answer:
im sorry i cant help you without a picture
Step-by-step explanation:
I can’t see can you put it closer
Answer: below
Step-by-step explanation: Given f(x) =kxn where k is a constant, then f'(x) = nkx(n - 1)
Can you apply this principle to this problem, Let me know if you have any further questions about this problem. Thanks.
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Answer:
Step-by-step explanation:
2x(x - 3) + 7(x - 3)
2x^2 - 6x + 7x - 21
reduce
2x^2 + x - 21
if this is equal to 0 then:
2x^2 + x - 21 = 0
factored:
(2x + 7)(x - 3) = 0
How that was done:
Divide the (2x^2) into (2x) and (x).
Divide the (-21) into (+7) and (-3). You choose these numbers so that their sum, when multiplied by (2x) and (-3), adds up to (+x).
