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Hatshy [7]
3 years ago
10

Can someone solve under section two, numbers one and two?

Physics
2 answers:
Novay_Z [31]3 years ago
8 0

1. Height of cube =9cm

mass of cube= 3645 g

volume= length ×breadth× height

as cubic volume so length breadth and heights are same so

volume =height ×height ×height

V =9cm×9cm×9cm= 729cm³

density =mass/ volume

density =3645g/729cm³

density= 5g/cm³

2.  AS DENSITY = mass/volume

volume =mass/ desity

volume= 13.558g/(0.089g/l)

volume= 0.152L³

ser-zykov [4K]3 years ago
3 0

Density = mass/volume

#1). The mass is given. And knowing the length of a cube's side, you can calculate its volume.

Volume = mass/density

#2). The mass and density are both given.

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3 years ago
A small block of mass 20.0 grams is moving to the right on a horizontal frictionless surface with a speed of 0.68 m/s. The block
Usimov [2.4K]

Answer:

a) v'=-0.227\ m.s^{-1}

b) v=1.36\ m.s^{-1}

Explanation:

Given:

mass of the lighter block, m'=0.02\kg

velocity of the lighter block, u'=0.68\ m.s^{-1}

mass of the heavier block, m=0.04\ kg

velocity of the heavier block, u=0\ m.s^{-1}

a)

Using conservation of linear momentum:

m'.u'+m.u=m'.v'+m.v

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v'= final velocity of the lighter block

v= final velocity of the heavier block

m'.u'=m'.v'+m.v

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divide the above equation by eq. (1)

v=u'+v' .............................(2)

now we substitute the value of v from eq. (2) in eq. (1)

m'(u'-v')=m(u'+v')

\frac{m'+m}{m'-m} =\frac{u'}{v'}

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b)

now we substitute the value of v' from eq. (2) in eq. (1)

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2m'.u'=(m-m')v

2\times 0.02\times 0.68=(0.04-0.02)\times v

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