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3 years ago

Can someone solve under section two, numbers one and two?

Physics

2 answers:

Novay_Z [31]3 years ago

8 0

1. Height of cube =9cm

mass of cube= 3645 g

volume= length ×breadth× height

as cubic volume so length breadth and heights are same so

volume =height ×height ×height

V =9cm×9cm×9cm= 729cm³

density =mass/ volume

density =3645g/729cm³

density= 5g/cm³

2. AS DENSITY = mass/volume

volume =mass/ desity

volume= 13.558g/(0.089g/l)

volume= 0.152L³

ser-zykov [4K]3 years ago

3 0

Density = mass/volume

#1). The mass is given. And knowing the length of a cube's side, you can calculate its volume.

Volume = mass/density

#2). The mass and density are both given.

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2 years ago

A copper rod 81 cm long is used to poke a fire. the hot end of the rod is maintained at 105° c and the cool end has a constant t

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The temperature inside the copper rod varies linearly with the distance from the hot end of the rod. This means that we can find the temperature at 23 cm (let's call it 'point A') from the cool end by solving a linear proportion.

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from which we find
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2 years ago

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3 years ago

A uniform meterstick of mass 0.20 kg is pivoted at the 40 cm mark. where should one hang a mass of 0.50 kg to balance the stick?

Tcecarenko [31]

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$d_1 = 0.50 m - 0.40 m=0.10 m$
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To keep the system in equilibrium, the mass of 0.50 kg must generate an equal torque with opposite direction of rotation, so it must be located at a distance d2 somewhere between x=0 and x=0.40 m. The magnitude of the torque should be the same, 0.20 Nm, and so we have:
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So, the mass should be put at x=-0.04 m from the pivot, therefore at the x=36 cm mark.

4 0

3 years ago