The total energy stored in the capacitors is determined as 2.41 x 10⁻⁴ J.
<h3>What is the potential difference of the circuit?</h3>
The potential difference of the circuit is calculated as follows;
U = ¹/₂CV²
where;
- C is capacitance of the capacitor
- V is the potential difference
For a parallel circuit the voltage in the circuit is always the same.
The energy stored in 2.5 μf capacitor is known, hence the potential difference of the circuit is calculated as follows;
U = ¹/₂CV²
2U = CV²
V = √2U/C
V = √(2 x 1.8 x 10⁻⁴ / 2.5 x 10⁻⁶)
V = 12 V
The equivalent capacitance of C1 and C2 is calculated as follows;
1/C = 1/C₁ + 1/C₂
1/C = (1)/(0.9 x 10⁻⁶) + (1)/(16 x 10⁻⁶)
1/C = 1,173,611.11
C = 1/1,173,611.11
C = 8.52 x 10⁻⁷ C
The total capacitance of the circuit is calculated as follows;
Ct = 8.52 x 10⁻⁷ C + 2.5 x 10⁻⁶ C
Ct = 3.35 x 10⁻⁶ C
The total energy of the circuit is calculated as follows;
U = ¹/₂CtV²
U = ¹/₂(3.35 x 10⁻⁶ )(12)²
U = 2.41 x 10⁻⁴ J
Learn more about energy stored in a capacitor here: brainly.com/question/14811408
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Answer:
Explanation:
Frictional force acting on incline = μ mg cosθ
μ is coefficient of friction , m is mass of object , θ is incline
= .09 x m x 9.8 x cos 28
= .78 m
work done by friction
= frictional force x displacement
= - .78m x 100
= - 78m
Potential energy of sli at height
= mgh
= m x 9.8 x 100 sin 28
= 460.08 m
net energy at the base
= 460.08m - 78 m
= 382.08 m
This will be in the form of kinetic energy .
1/2 m v² = 382.08 m
.5 x v² = 382.08
v = 27.64 m/s
After that it travels on plane surface .
Let the distance travelled be d
work done by frictional force
= μ mg x d
= .09 x m x 9.8 x d
This will be equal to kinetic energy at the base
.09 x m x 9.8 x d = 382.08 m
d = 433.2 meter .
A convergent plate movement happened, this movement also cause the Himalayan mountains, where Mt. Everest is located.
Hope this helps!
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