The correct words to fill the given blanks would be as follows:
- Peak
- Trough
- Equilibrium Line
- Oscillation
- Frequency, Hertz
- Period, seconds
- The "peak" is denoted as the highest or maximum point that the wave attains while 'Trough' is characterized as the base of the wave.
- The 'equilibrium line' is characterized as the extent to which the wave flattens or compresses.
- Oscillation is defined as the process in which an object moves in the "back and forth motion."
- Frequency is the amount of occurrences that waves travel in a second which is denoted in the terms of Hertz.
- Lastly, period is the duration required by wave to accomplish one motion is denoted in terms of seconds.
- Amplitude is the breadth or magnitude of the waves.
Learn more about "Oscillation" here:
brainly.com/question/9820984
Answer:
Also 0
Explanation:
Since average speed of an object is that object's displacement over a unit of time, when an average speed is 0, its displacement over a unit of time must also be 0. When an average speed is not 0, then its displacement over a unit of time is also not 0 for that interval.
The R1, R2, R3, R5 and R6 contains current and R4, R7, R8 and R9 do not contain current. Since R8 loop voltages sources cancel VR8 + V – V = 0 so VR8 = 0. The top of R9 potential from ground is +V + V + V – V - V = V. The bottom of R9 potentials from ground is V so VR9 = 0. The left of R7 potential from ground is +V + V – V = V. The right side of R7 potential from ground is +V + V +V – V – V = V. Therefore, VR7 = 0. From the ground the left side of R4 = +V and from the ground the right side or R4 is at V so VR4 = 0. Since we know that R1 must have 2V across it and we know that R6 and R3 each have V/2, R2 has V across it and R5 must have V across it because the potential of its left end from the ground = +V + V = 2V but the potential of its right end from the ground must be +V + V + V – V – V = V.
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